Since the Mean Value Theorem is applicable, at least one point c exists in (0, 1) such that f'(c) = . To find c, first evaluate f(1)-f(0) (1)4/5 - (0)4/5 1-0 1-0 = f(1)-f(0) 1-0 Next, determinef'(x). f(x)=x4/5 f(1)-f(0) 1-0
Since the Mean Value Theorem is applicable, at least one point c exists in (0, 1) such that f'(c) = . To find c, first evaluate f(1)-f(0) (1)4/5 - (0)4/5 1-0 1-0 = f(1)-f(0) 1-0 Next, determinef'(x). f(x)=x4/5 f(1)-f(0) 1-0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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