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Since the velocity components are a function of position only, the flow can be m/s and v= 2 m/s. The classified as steady nonuniform flow. Here u slope of the streamline is defined by From th WED dy 2-5 dx 3m (0.5y²) m dy dx 0.5y ²dy=4fdx 3-4 13 m Im y³12x + 15

Since the velocity components are a function of position only, the flow can be m/s and v= 2 m/s. The classified as steady nonuniform flow. Here u slope of the streamline is defined by From th WED dy 2-5 dx 3m (0.5y²) m dy dx 0.5y ²dy=4fdx 3-4 13 m Im y³12x + 15

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How you got the 4/y^2 , please step by step
SOLUTION Since the velocity components are a function of position only, the flow can be classified as steady nonuniform flow. Here u = (0.5y²) m/s and v= 2 m/s. The slope of the streamline is defined by From the definiti dy dx dy dx y'dy 3m m 0.5 Im y³12x + 15
Transcribed Image Text:SOLUTION Since the velocity components are a function of position only, the flow can be classified as steady nonuniform flow. Here u = (0.5y²) m/s and v= 2 m/s. The slope of the streamline is defined by From the definiti dy dx dy dx y'dy 3m m 0.5 Im y³12x + 15
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