Situation 10: Given Beam Data and use 2010 NSCP: erenc Beam width, b = 300 mm A Concrete, f'c = 21 MPa Stirrups = 2 legs, 10 mm e 32. The required spacing of the stirrups if Vu = 50 KN. Effective depth, d = 600 mm Steel Strength, fyt = 275 MPa Ostirups = 0.75 a. 100 b. 150 c. 200 d. NOTA 33. The required spacing of the stirrups if VU = 100 KN. a. 100 c. 300 b. 200 d. NOTA 34. The required spacing of the stirrups if VU = 200 KN. а. 100 35. The required spacing of the stirrups if Vu = 550 KN. b. 200 c. 300 d. NOTA а. 100 Situation 11: c. 200 b. 150 d. NOTA A reinforced concrete beam has a width of 300mm and an effective depth of 510 mm. It supports a factored uniform load of 68 KNm providing a maximum factored shear at face of the support equal to 220 kN. Use normal weight concrete and f'c = 24 MPa. For the shear reinforcements, fg = 275 MPa. Use the simplified method for calculating shear of the 2010 NSCP. 36. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm x 350 mm girder. а. 1.34 37. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm square column. а. 1.92 38. Find the value of the factored shear stress in MPa from the shear standpoint that no web reinforcements will be required for the section. b. 1.81 c. 1.70 d. 1.92 b. 1.42 c. 0.83 d. 1.61

Structural Analysis
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Chapter2: Loads On Structures
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Situation 10:
困
Given Beam Data and use 2010 NSCP:
File
Home
Insert
Draw
Design Layout
Referenc
& Share
Beam width, bw = 300 mm
Concrete, f'c = 21 MPa
Effective depth, d = 600 mm
X Cut
O Find
Calibri (Body)
11
A A
Steel Strength, fyt = 275 MPa
e Copy
abc Replace
Stirrups = 2 legs, 10 mm o
32. The required spacing of the stirrups if Vu = 50 KN.
Paste
Ostirrups = 0.75
BI U v abe X, x
V Format Painter
A Select -
Clipboard
Font
Editing
d. 100
а. 100
b. 150
с. 200
d. NOTA
33. The required spacing of the stirrups if VU = 100 KN.
а. 100
b. 200
с. 300
d. NOTA
34. The required spacing of the stirrups if VU = 200 KN.
а. 100
b. 200
С. 300
d. NOTA
35. The required spacing of the stirrups if Vu = 550 KN.
а. 100
b. 150
с. 200
d. NOTA
Situation 11:
A reinforced concrete beam has a width of 300mm and an effective depth of 510 mm. It supports a factored
uniform load of 68 KNm providing a maximum factored shear at face of the support equal to 220 kN. Use normal
weight concrete and f'c = 24 MPa. For the shear reinforcements, fyt = 275 MPa. Use the simplified method for
calculating shear of the 2010 NSCP.
36. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm x 350
mm girder.
а. 1.34
37. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm
b. 1.81
с. 1.70
d. 1.92
square column.
а. 1.92
b. 1.42
c. 0.83
d. 1.61
38. Find the value of the factored shear stress in MPa from the shear standpoint that no web reinforcements will
be required for the section.
Page 3 of 9
4145 words
English (United States)
K Accessibility: Investigate
130%
ENG
9:34 am
amazon
w
R888
US
06/03/2022
Transcribed Image Text:Situation 10: 困 Given Beam Data and use 2010 NSCP: File Home Insert Draw Design Layout Referenc & Share Beam width, bw = 300 mm Concrete, f'c = 21 MPa Effective depth, d = 600 mm X Cut O Find Calibri (Body) 11 A A Steel Strength, fyt = 275 MPa e Copy abc Replace Stirrups = 2 legs, 10 mm o 32. The required spacing of the stirrups if Vu = 50 KN. Paste Ostirrups = 0.75 BI U v abe X, x V Format Painter A Select - Clipboard Font Editing d. 100 а. 100 b. 150 с. 200 d. NOTA 33. The required spacing of the stirrups if VU = 100 KN. а. 100 b. 200 с. 300 d. NOTA 34. The required spacing of the stirrups if VU = 200 KN. а. 100 b. 200 С. 300 d. NOTA 35. The required spacing of the stirrups if Vu = 550 KN. а. 100 b. 150 с. 200 d. NOTA Situation 11: A reinforced concrete beam has a width of 300mm and an effective depth of 510 mm. It supports a factored uniform load of 68 KNm providing a maximum factored shear at face of the support equal to 220 kN. Use normal weight concrete and f'c = 24 MPa. For the shear reinforcements, fyt = 275 MPa. Use the simplified method for calculating shear of the 2010 NSCP. 36. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm x 350 mm girder. а. 1.34 37. Find the design nominal shear in MPa at the critical section for shear if the beam is framed to a 350mm b. 1.81 с. 1.70 d. 1.92 square column. а. 1.92 b. 1.42 c. 0.83 d. 1.61 38. Find the value of the factored shear stress in MPa from the shear standpoint that no web reinforcements will be required for the section. Page 3 of 9 4145 words English (United States) K Accessibility: Investigate 130% ENG 9:34 am amazon w R888 US 06/03/2022
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