1. List the given required.2. Graph if necessary.3. Box the final answer. SITUATION 2-A confined aquifer underlies an unconfined aquifer as shown in the figure.Given the following: D₁= 55 m, D₂- 42 m, H 45 m, H₂= 30 m, KF 45 mvday, K₂= 20m/day, L= 2.1 km.4. Calculate the equivalent coefficient of permeability (in m/day) in horizontaldirection.5. Calculate the flow of water from one stream to another per meter width in m³/day.DiM₁H₂0₂

Answered: Image /qna-images/answer/86da6411-fb5f-4125-a717-c2550ac32ef8.jpg

Answered: SITUATION 2-A confined aquifer…

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter7: Permeability

Section: Chapter Questions

Problem 7.5P

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For the two-dimensional flow system shown below (units in meters):Compute the total flow rate under the Dam. X = 4, Y = 8. Note 1: Point A is located in the middle point of the equipotential lines. Point B is located in the middle point of the flow lines.Note 2: Assume e=0.8 (void ratio) and k=10^-3 cm/s (coeff. of permeability).Note 3: Datum is located at the bottom level of the water (right side of Dam).Note 4: Remember, the figure is drawn to scale. So, use the value of 2X+Y to estimate any dimension that you consider necessary.
9. From the figure shown: (See picture below) Cross-sectional area = 0.6m2 Hydraulic Conductivity of sand = 0.1 cm/sec What is the rate of upward seepage of water? (Answer: 360 cm3/sec) What would be the critical hydraulic gradient? (Answer: 1.12 m) What value of h to cause boiling? (Answer: 2.8 m)
Refer to Problem 8.4. Using the flow net drawn, calculate the hydraulic uplift force at the base of the hydraulic structure per meter length (measured along the axis of the structure).8.24 For the hydraulic structure shown in Figure 8.24, draw a flow net for flow through the permeable layer and calculate the seepage loss in m3/day/m.
Given the coefficient k =0.05 m/s and porosity p = 48%, find thetransmissibility (T) in m/s per unit m, if the aquifer width is 1.2 m.Formula: - It is the flow rate per day thru a unit areaunder a unit hydraulic gradient For an aquifer with thickness, Band width, X:T = K*B and Ag = BXThus: Q = (T*X*S)
Solve for the ratio of equivalent hydraulic conductivity with the following given: h1 = 2 m h2 = 2.5 m h3 = 1.8 m h4 = 0.9 m k1 = 1.5E-3 cm/sec k2 = 2.2E-4 cm/sec k3 = 1.6E-4 cm/sec k4 = 4.0E-4 cm/sec What is the equivalent coefficient of permeability if the water flows perpendicular to the layer of soil (KeqV) in cm/sec?
11. A channel runs almost parallel to a river as shown in the figure. The water level in the river has an elevation of 36 m. and the elevation of the channel is 33 m. The river and channel are 600 m apart and a previous formation of the average thickness of 9 m and hydraulic conductivity of 0.80 m/hr joints them together. Compute the hydraulic gradient Compute the rate of seepage flow from the river to the channel per meter width in liters per day. If the seepage velocity is 0.048 m/day, compute the void ratio of the previous medium.
From the figure shows an unconfined non homogeneous aquifer between two water bodies at depth of 50 m and 45 m. respectively. Compute the average coefficient of permeability of the aquifer and the rate of flow.
Solve for the ratio of equivalent hydraulic conductivity with the following given: h1 = 2 m h2 = 2.5 m h3 = 1.8 m h4 = 0.9 m k1 = 1.5E-3 cm/sec k2 = 2.2E-4 cm/sec k3 = 1.6E-4 cm/sec k4 = 4.0E-4 cm/sec What is the equivalent coefficient of permeability if the water flows parallel to the layer of soil (KeqH) in cm/sec?
A confined aquifer has a thickness of 85 ft. An 86-in diameter well drilled to the bottom of the aquifer, as shown in fig 3-10, if the hydraulic conductivity of the aquifer is 10 ft / day, and if water is originally 170 ft deep in the well, calculate approximately the maximum rate of flow that can be pumped from the well without dewatering any part of the aquifer. Assume 1000 ft reasonable value for the radius of influence. What will be the average velocity ( Darcy velocity ) of flow in the aquifer at a distance 20 ft from the center of the well?
A confined aquifer bed with a varying thickness as shown in the following figure. The aquifer hydraulic conductivity is 15 m/day. The piezometric heads at x=0 is 15.5m and at x=2000m, head is 22.1m. Determine the flow rate per unit width assuming the flow in theaquifer is essentially horizontal.
CALCULATION USING DARCY'S LAW An aquifer system is formed by two horizontal layers. Two piezometers were installed for monitoring, the distance between them is 885m. The upper layer (A) has a thickness of 39m and K = 1.3 x 10-5 m/s and the lower layer (B) has a thickness of 25m and K = 2.7 x 10-6 m/s. THE hydraulic load in the PZA is 60m and in the PZB it is 40m. Calculate the flow and the transmissivity of each layer.
Find the rate of flow in m^3/sec/m (at right angles to the cross-section shown in Figure 7.33) through the permeable soil layer. Given: H 4 m, H1 2 m, h 2.75 m, S 30 m, a 14°, and k 0.075 cm/sec.

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