Situation 3. The trame is loaded as ilustrated in Figure 3 and is hinged at point C. Sketch the shear, bending moment, and axial diagrams. Also draw the qualitative defiected shape as an overlay on the original frame. 15 KN/m 2m S0 N 80 AN 4 m 2.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Situation 3. The trame is loaded as illustrated in Figure 3 and is hinged at point C. Sketch the shear, bending
moment, and axial diagrams. Also draw the qualitative deflected shape as an overlay on the original frame.
15 kN/m
2m
50 kN
80 AN
2 m
4 m
3 m
3m
Figure 3
Transcribed Image Text:Situation 3. The trame is loaded as illustrated in Figure 3 and is hinged at point C. Sketch the shear, bending moment, and axial diagrams. Also draw the qualitative deflected shape as an overlay on the original frame. 15 kN/m 2m 50 kN 80 AN 2 m 4 m 3 m 3m Figure 3
Expert Solution
Step 1 Interpretation of data

Data given:

Civil Engineering homework question answer, step 1, image 1

Asked:

  • Sketch shear, Bending moment and Axial force diagram

 

Step 2 Primary calculations

Consider following free body diagram for given frame:

Civil Engineering homework question answer, step 2, image 1

The angle θ can be obtained by,

θ = tan-126 = 18.44°

Take summation of moment at C = 0,

 VE × 3 - 15 × 6.3252 × 6.3254 - (50 × 1) = 0 VE = 41.67 kN

Take V = 0,

 VA +VE = 15 × 6.325 VA +VE = 94.875 kN VA = 94.875 - 41.67 = 53.2 kN

Finally, consider H = 0,

HA = 80 - 50 = 30 kN

In order to find Moment at A. let's again consider summation of moment at point C from left hand side,

- MA + 53.2 × 3 + (30 × 5) - (80 × 1) - 15 × 6.3252 × 6.3254 = 0 MA = 154.6 lN-m

 

 

 

Step 3 Calculations for axial force diagram

In member AB,Axial force = 53.2 kNIn member DE,Axial force = 41.67 kNIn member BDAxial force = (80-30) × sin18.44° +(53.2 × cos18.44°) = 66.28 kN

Civil Engineering homework question answer, step 3, image 1

 

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