Homework Help is Here – Start Your Trial Now!
Science
Physics
Siven two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10-10 C at the origin. (Note: Assume a reference level of potential V = 0 at r= 0.) x= -0,800 m x= 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-uC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-uC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 3.20-uc particles?

Siven two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 10-10 C at the origin. (Note: Assume a reference level of potential V = 0 at r= 0.) x= -0,800 m x= 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-uC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-uC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 3.20-uc particles?

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 9P: Given two particles with 2.00-C charges as shown in Figure P20.9 and a particle with charge q = 1.28...
See similar textbooks
icon
Related questions
Question
100%
Given two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 1018 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.) x = -0.800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-µC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-µC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge were moved a distance d = 0.400 m closer to either of the 3.20-µC particles?
Transcribed Image Text:Given two particles with Q = 3.20-µC charges as shown in the figure below and a particle with charge q = 1.37 x 1018 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.) x = -0.800 m x = 0.800 m (a) What is the net force (in N) exerted by the two 3.20-uC charges on the charge q? (Enter the magnitude.) (b) What is the electric field (in N/C) at the origin due to the two 3.20-µC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 3.20-µC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge were moved a distance d = 0.400 m closer to either of the 3.20-µC particles?
Expert Solution
Step 1

"As per the guidelines i solved the first three subpart".

(a)

Since, the two charges are equal in magnitude and at equal distance from the origin, the magnitude of the force on charge q due to both are equal.

The two charges are located on opposite sides of the test charge, the forces are in opposite direction.

Therefore, the resultant of the two equal and opposite forces on the charge q will be equal to zero.

(b)

The electric field at the origin due to the two charges is,

E=Fq=0

Therefore, the resultant electric field at origin due to the two charges is zero.

 

 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS