Draw the structure of the product of the reaction between the compound shown below and BF3. CH3CH₂OH • You do not have to consider stereochemistry. You do not have explicitly draw H atoms. • If the reaction involves proton transfer, draw the products in separate sketchers. • If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only. 7-8 3 9.85 OOO. SIF Base + Acid H₂COH изсизон ChemDoodle remove 226 22 4 ·000- F ChemDoodle Conj. base Com). *182 GRA 0. 000. SIF H₂co ChemDoodle Conjacid ✔399-8 H▾ 000 ChemDoodleⓇ

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter4: Acids And Bases
Section: Chapter Questions
Problem 4.32P: For each equation, label the Lewis acid and the Lewis base. In addition, show all unshared pairs of...
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Draw the structure of the product of the reaction between the compound shown below and BF3.
CH3CH₂OH
• You do not have to consider stereochemistry.
• You do not have to explicitly draw H atoms.
• If the reaction involves proton transfer, draw the products in separate sketchers.
• If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only.
ag
**8
Acid •
Base
H₂COH
+
идензон
ChemDoodleⓇ
+
remove
ChemDoodleⓇ
Sn [F
e▾
Cons. base
00
H₂CO
ChemDoodleⓇ
Sn [F
+
H▾
Conjacid
90-85
ChemDoodleⓇ
Transcribed Image Text:Draw the structure of the product of the reaction between the compound shown below and BF3. CH3CH₂OH • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • If the reaction involves proton transfer, draw the products in separate sketchers. • If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only. ag **8 Acid • Base H₂COH + идензон ChemDoodleⓇ + remove ChemDoodleⓇ Sn [F e▾ Cons. base 00 H₂CO ChemDoodleⓇ Sn [F + H▾ Conjacid 90-85 ChemDoodleⓇ
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So, in this lewis acid-base reaction, do we need to draw lone pairs or not? Why or why not? Thank you.

H₂
H3C-
-OH F
+
LL
F
LL
H3C-
H₂
-CO
F-B
HO
LL
Transcribed Image Text:H₂ H3C- -OH F + LL F LL H3C- H₂ -CO F-B HO LL
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