So we found that the slope of the tangent line at x = 36 is 12 , and that (36, 6) is a point on the line. Substituting these values into the point-slope formula y - Yo = m(x - xo), we have y-Yo = m(x – xo) y - 6 = (x- 36) 12 Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is %3D y =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.10: Partial Fractions
Problem 12E
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Part 3 of 4
Using the factorization x – 36 = (/x – 6)(/x + 6), we have
9 – x^
x→36 (/x - 6)(/x + 6)
Vx – 6
mtan
lim
%3D
1
lim
(Vx
+ 6)
VI+6
X→36
= 1/12
1/12
Part 4 of 4
1
and that (36, 6) is a point on the line.
12
So we found that the slope of the tangent line at x = 36 is
%3D
Substituting these values into the point-slope formula y – Yo = m(x – x0), we have
y – Yo = m(x – xo)
y – 6 =
-(х - 36)
12
|
Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is
%3D
y =
Transcribed Image Text:Part 3 of 4 Using the factorization x – 36 = (/x – 6)(/x + 6), we have 9 – x^ x→36 (/x - 6)(/x + 6) Vx – 6 mtan lim %3D 1 lim (Vx + 6) VI+6 X→36 = 1/12 1/12 Part 4 of 4 1 and that (36, 6) is a point on the line. 12 So we found that the slope of the tangent line at x = 36 is %3D Substituting these values into the point-slope formula y – Yo = m(x – x0), we have y – Yo = m(x – xo) y – 6 = -(х - 36) 12 | Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is %3D y =
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