SOLUTION The y-intercept is f(0) = (-3) and the x-intercepts are found by setting y = 0: x = 3, 1, Notice that since (x - 3)4 is positive, the function doesn't change sign at 3; thus the graph doesn't cross the x-axis at 3. The graph crosses the axis at -1 and When x is large positive, all three factors are positive, so lim (x - 3)4(x + 1)(x - 1) - o, X+ 00 When x is large negative, the first factor is large positive and the second and third factors are both large negative so lim (x - 3)*(x + 1) (x - 1) = co, Combining this information, we give a rough sketch of the graph in the figure below.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 23SE: For the following exercises, consider the graph shown in Figure 16. Estimate the point(s) at which...
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Sketch the graph of y = (x – 3)“(x + 1)(x – 1) by finding its intercepts and its limits as x → ∞ and x → -.
SOLUTION
The y-intercept is f(0) = (-3)(
and the x-intercepts are found by setting y = 0: x = 3, 1,
Notice that since (x - 3)4 is positive, the function doesn't change sign at 3; thus the graph doesn't
cross the x-axis at 3. The graph crosses the axis at -1 and
When x is large positive, all three factors are positive, so
lim (x - 3) (x + 1)3(x – 1) =
= 0.
X → 00
When x is large negative, the first factor is large positive and the second and third factors are both large negative so
lim (x - 3)*(x + 1)°(x - 1) = 0.
X → -00
Combining this information, we give a rough sketch of the graph in the figure below.
y
3
-81
Transcribed Image Text:Sketch the graph of y = (x – 3)“(x + 1)(x – 1) by finding its intercepts and its limits as x → ∞ and x → -. SOLUTION The y-intercept is f(0) = (-3)( and the x-intercepts are found by setting y = 0: x = 3, 1, Notice that since (x - 3)4 is positive, the function doesn't change sign at 3; thus the graph doesn't cross the x-axis at 3. The graph crosses the axis at -1 and When x is large positive, all three factors are positive, so lim (x - 3) (x + 1)3(x – 1) = = 0. X → 00 When x is large negative, the first factor is large positive and the second and third factors are both large negative so lim (x - 3)*(x + 1)°(x - 1) = 0. X → -00 Combining this information, we give a rough sketch of the graph in the figure below. y 3 -81
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