Solve each equation by factoring. The image below is an example of this.1.) 2?^2 + 23? − 25 = 0 2.) 3x^2-5x = -12 1. 2х2 — 11х+ 15 3 0ас %3 (2)(15) %3D 30ac =step 130 = {(2,15), (3,10), (-6, –5)}step 22х2 — 6х — 5х + 15 — 0%3Dstep 3(2x2 — 6х) — (5х — 15) %3D 02x(х — 3) — 5(х — 3) %3D 0step 4|-step 5|(2х — 5) (х — 3) %3D 0-step 6|2х—5 %3D 0 апd x — 3 3D 0step 7-2x = 5 and x = 3,Therefore, the roots are x1 =; and x2 = 32

2x2+23x-25=0ac=-50-50=[(1,-50),(-2,25),(2,-25),(-10,5),(10,-5),(50,-1)]2x2-2x+25x-25=0(2x2-2x)+(25x-…

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Solve each equation by factoring. The image below is an example of this. 1.) 2?^2 + 23? − 25 = 0 2.) 3x^2-5x = -12

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter11: Topics From Analytic Geometry

Section: Chapter Questions

Problem 47RE

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A: Topic = Quadratic equation

Question

Solve each equation by factoring. The image below is an example of this.

1.) 2?^2 + 23? − 25 = 0

2.) 3x^2-5x = -12

1. 2х2 — 11х+ 15 3 0
ас %3 (2)(15) %3D 30
ac =
step 1
30 = {(2,15), (3,10), (-6, –5)}
step 2
2х2 — 6х — 5х + 15 — 0
%3D
step 3
(2x2 — 6х) — (5х — 15) %3D 0
2x(х — 3) — 5(х — 3) %3D 0
step 4
|
-
step 5
|
(2х — 5) (х — 3) %3D 0
-
step 6
|
2х—5 %3D 0 апd x — 3 3D 0
step 7
-
2x = 5 and x = 3,
Therefore, the roots are x1 =; and x2 = 3
2

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