Solve for the Following Bending moment equation for segment BC. a. 2000 lb(X) - 100 lb/ft (X squared) - 9600 lb-ft b. 2100 lb(X) - 120 lb/ft (X squared) - 9700 lb-ft c. 21500 lb(X) - 200 lb/ft (X squared) - 9800 lb-ft d. 3000 lb(X) - 200 lb/ft (X squared) - 9850 lb-ft The distance between point A and the shear force VAB=0 a. 6 feet b. 8 feet c. 10 feet d. 12 feet The degree of bending moment equations for segments AB and BC. a. 1st degree and 2rd degree b. 3rd degree and 2nd degree c. 2nd degree and 3rd degree d. None of the above.
Solve for the Following Bending moment equation for segment BC. a. 2000 lb(X) - 100 lb/ft (X squared) - 9600 lb-ft b. 2100 lb(X) - 120 lb/ft (X squared) - 9700 lb-ft c. 21500 lb(X) - 200 lb/ft (X squared) - 9800 lb-ft d. 3000 lb(X) - 200 lb/ft (X squared) - 9850 lb-ft The distance between point A and the shear force VAB=0 a. 6 feet b. 8 feet c. 10 feet d. 12 feet The degree of bending moment equations for segments AB and BC. a. 1st degree and 2rd degree b. 3rd degree and 2nd degree c. 2nd degree and 3rd degree d. None of the above.
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.76P: The 50-ft measuring tape weighs 2.4 lb. Compute the span L of the tape to four significant figures.
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Solve for the Following
Bending moment equation for segment BC.
a. 2000 lb(X) - 100 lb/ft (X squared) - 9600 lb-ft
b. 2100 lb(X) - 120 lb/ft (X squared) - 9700 lb-ft
c. 21500 lb(X) - 200 lb/ft (X squared) - 9800 lb-ft
d. 3000 lb(X) - 200 lb/ft (X squared) - 9850 lb-ft
The distance between point A and the shear force VAB=0
a. 6 feet
b. 8 feet
c. 10 feet
d. 12 feet
The degree of bending moment equations for segments AB and BC.
a. 1st degree and 2rd degree
b. 3rd degree and 2nd degree
c. 2nd degree and 3rd degree
d. None of the above.
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