Solve for the following problems involving the number of sample size: 1. Find the sample size, n to estimate the number of adults that consults their physician. Use a 0.06 margin of error and use 90% confidence level with a prior data that only 43% of the adults consult their physician. a. What is the exact value of Z? b. What is the exact value of p? c. What is the value of q?

Q: If n=17, ¯xx¯(x-bar)=41, and s=7, find the margin of error at a 80% confidence level Give your…

A: Sample mean = 41 Standard deviation = 7 Sample size = 17 80% confidence level

Q: For a population data set, σ = 13.3 . How large a sample should be selected so that the margin of…

A: From the given information, confidence level  Level of significance  Margin of error E = 2.50.…

Q: If n=31, ¯xx¯(x-bar)=38, and s=4, find the margin of error at a 95% confidence level Give your…

A: Here, the population standard deviation is unknown. Hence, t - distribution is appropriate to use as…

Q: Suppose we have the following information for two independent samples: I2 = 48 35 I1= 33 %3D %3D S1…

A: Given information: The two-independent samples are taken at random. The first sample yields the…

Q: Solve the following problems. Do not use pencil. 1. a randomly selected 80 scores from the scores of…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: If n=19, ¯xx¯(x-bar)=31, and s=9, find the margin of error at a 90% confidence level Give your…

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Q: It is known that the population range equals 60. With a 95% confidence level, the sample size that…

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Q: If n=16, x(x-bar)=43, and s=9, find the margin of error at a 99% confidence level Give your answer…

A: The random variable X follows normal distribution. The sample size is 16. The sample mean is 43. The…

Q: 20 The following is an interval estimate with a 95% confidence level for the proportion of Indiana…

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Q: If n=20, ¯xx¯(x-bar)=44, and s=9, find the margin of error at a 98% confidence level Give your…

A: In the question, n=20 and s=9 are given and the margin of error at a 98% confidence level is asked…

Q: For a population data set, o = 13.40. a. What should the sample size be for a 98% confidence…

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Q: If n=11, ¯x(x-bar)=35, and s=8, find the margin of error at a 90% confidence level Give your answer…

A: Given that,  n=11, x-bar=35, and s=8, Confidence level is 90%

Q: If n=12, ¯xx¯(x-bar)=41, and s=10, find the margin of error at a 80% confidence level Give your…

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Q: If n=13, x(x-bar)=30, and s=9, find the margin of error at a 99% confidence level Give your answer…

A: Given,n=13x=30s=9α=1-0.99=0.01α2=0.005degrees of freedom(df)=n-1=13-1=12t0.005(12)=3.055

Q: For each problem, a) find the difference between the two sample proportions. b) use Confidence…

A: Given; x1=377, n1=422x2=431, n2=518p^1=x1n1=377422=0.8934p^2=x2n2=431518=0.8320 (a) The difference…

Q: If n=24, x(x-bar)=33, and s=3, find the margin of error at a 90% confidence level Give your answer…

A: It is given that standard deviation (s) is 3 and sample size (n) is 24.

Q: If n=12, ¯x(x-bar)=35, and s=2, find the margin of error at a 98% confidence level Give your…

A: Given: n=12 ¯x(x-bar)=35 s=2

Q: If n=22, ¯xx¯(x-bar)=45, and s=9, find the margin of error at a 95% confidence level Give your…

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Q: Use Appendix B.5 to locate the value of t under the following conditions. a. The sample size is 12…

A: We have given sample size "n" and confidence level we have to find t value for that.since we know…

Q: A television sports commentator wants to estimate the proportion of citizens who​ "follow…

A: Solution: a. From the given information, confidence level is 0.96, p=0.48 and E=0.03.

Q: A random sample of 35 two-year colleges in 2014-2015 had a mean tuition (for in-state students) of…

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Q: If n=13, ¯x(x-bar)=41, and s=5, find the margin of error at a 80% confidence level Give your answer…

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Q: If n=23, ¯x(x-bar)=34, and s=8, find the margin of error at a 99% confidence level Give your answer…

A: Solution: From the given information, n=23, x-bar=34 and s=8. The confidence level is 0.99.

Q: If n=n= 22, x= 32, and s= 16, construct a confidence interval at a 99% confidence level. Assume the…

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Q: In Italy, Totti has four restaurants in the capital Roma. The manager is concerned that there is a…

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Q: Find a 99% confidence interval for the previous problem. (30.19, 32.21) (30.26, 32.14) O (31.195,…

A: Given information Sample size (n) = 30 Sample mean x̅ = 31.2 gallons Standard deviation (s) = 2…

Q: If n=17, ¯xx¯(x-bar)=47, and s=4, find the margin of error at a 80% confidence levelGive your answer…

A: Given data Sample size (n) = 17 x̅ = sample mean = 47 s = sample standard deviation = 4 Confidence…

Q: If n=19, x= 47, and s = 8, find the margin of error at a 99% confidence level Give your answer to…

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Q: 5. If the error for estimating µu was within 4 units, how many should we sample at 98% Confidence…

A: Given information- Error, E = 4 units Confidence level, c = 98% Standard deviation, s = 29 Margin of…

Q: If n=15, ¯xx¯(x-bar)=37, and s=9, find the margin of error at a 80% confidence level Give your…

A: Given that  n = 15 , x- = 37 , s = 9

Q: If n=11, ¯xx¯(x-bar)=35, and s=8, find the margin of error at a 90% confidence level. Answer to two…

A: Margin of error = t critical * Standard error where    t critical is the value of t for 90%, two…

Q: For a population data set, o = 11.60. a. What should the sample size be for a 98% confidence…

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Q: If n=12, ¯xx¯(x-bar)=48, and s=6, find the margin of error at a 98% confidence level

A: From the provided information, Sample size (n) = 12 Sample mean (x̄) = 48 Standard deviation (s) = 6…

Q: It is believed that 25% of U.S. homes have a direct satellite television answers up to a whole…

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Q: If n=14, ¯xx¯(x-bar)=33, and s=8, find the margin of error at a 80% confidence level Give your…

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Q: The last result in each set of data in Problem 7-4 may be an outlier. Apply the Q test (95%…

A: Given, the last result in each set of data in problem is an outlier. Arrange all the data in…

Q: For each of the following problems, (a) Write the important information, (b) Verify the CLT…

A: Given,n=1028x=617sample proportion(p^)=xnsample proportion(p^)=6171028sample…

Q: Use the given data to find the minimum sample size required to estimate the population proportion.…

A:

Q: If n=15, (x-bar)=46, and s=3, find the margin of error at a 90% confidence level Give your answer to…

A: According to the given information, we haveSample size, n = 15Sample mean = 46Sample standard…

Q: Find the margin of error for the given 1. o = 3.5 n = 45 a. 90% confidence level

A: To find the margin of error for the given confidence levels: Margin of error indicates how many…

Q: If n=17, x bar = 39, and s=8, find the margin of error at a 99% confidence level.  Give the answer…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: Step 1 Recall that for a 95% confidence level, the formula for the sample size n required to…

A: The true value of the population proportion p is unknown. To use the formula for sample size, we…

Q: If n=13, x(x-bar)=31, and s=4, find the margin of error at a 95% confidence level   Give your…

A: n = 13 Mean = 31 Sample standard deviation = 4 95% confidence level

Q: If n=14, ¯xx¯(x-bar)=46, and s=6, find the margin of error at a 90% confidence level Give your…

A: We have given that,  Sample mean ( x̄) = 46, standard deviation   (s)=6 , sample size (n) = 14 and…

Q: If n=23, x(x-bar)=47, and s=3, find the margin of error at a 98% confidence level Give your answer…

A: Margin error is the difference between the estimated value and the original value. Here the critical…

Q: If n=10, ¯xx¯(x-bar)=44, and s=8, find the margin of error at a 80% confidence level

A:

Q: If n=12, x¯(x-bar)=47, and s=3, find the margin of error at a 80% confidence level

A: Margin of error (E): The margin of error for sample mean is given by,

Q: If n=16, ¯xx¯(x-bar)=45, and s=7, find the margin of error at a 95% confidence level Give your…

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Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.