Solve for the -quivalent spring constant for he given spring setup.
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- (5) A gas engine valve spring is loaded to 35kgf when the valve is closed & 52kgf hen the valve is open. The valve lift is 8mm. The outside diameter is to be from 38mm~45mm, & the permissible stress is 413N/mm2 . Determine: (a) the wire & outside diameter; (b) the number of effective coils; (c) the free length when it is squared & ground.For the helical compressive spring under fatigue load must meetPROBLEM:2 A spring made from a wire of 2.5 mm diameter and 750 N/sq. mm. as its working stress Mean diameter of 12.5 mm and 15 active coils. Find (a) Stiffness of the spring (b) solid length. Assume that the ends are squared and ground. Take modulus of rigidity as 0.85x105 N/mm2.
- 5. Design a helical compression spring for a maximum load of 1000 N and deflection of 25mm taking Wahl’s factor into consideration. Assume spring index as 5, maximum permissible shear stress for spring wire as 420 MPa and modulus of rigidity as 84 kN/mm2Find the number of active coils of a No. 10 wire Helical Spring index of 7, steady load with spring rate of 46.5 lb/in. maximum allowable stress is 70 ksi. The stiffness of a spring is 98 N/mm of axial compression. Find the Joules of work to increase the compression from 60 mm to 90 mm.Design a helical torsion spring that must give a minimum moment of Mmin (lb-in) and a maximum moment of Mmax (lb-in) over a dynamic deflection of 90o. An infinite life is desired. Use a factor of safety of 1.5 to estimate wire diameter. State all assumptions.
- Solve the following second order spring–mass system and state whether the motion is underdamped,critically damped, or over-damped.A semi-elliptic spring used for automobile suspension, consists of twoextra full-length leaves and eight graduated-length leaves, including themaster leaf. The centre-to-centre distance between the two eyes is 1 m.The leaves are made of steel 55Si2Mo90 (S = 1500 N/mm yt2 andE = 207 000 N/mm2) and the factor of safety is 2. The maximum springload is 30 kN. The leaves are pre-stressed so as to equalize stresses in allleaves under maximum load. Determine the dimensions of thecross-section of the leaves and the deflection at the end of the spring.A spring made from music wire ASTM 228 steel has the following data:Free length=1.75” Outside diameter=0.561”Wire diameter=0.055” Applied load= 14 lbEnds=square and ground both ends hingedNumber of coils=10 G=11.85 x 106psi E= 30 Mpsi Findspring rate, force at solid length,check for buckling,coil clearance and hole diameter
- A typical compound helical spring consists of two coaxial closed coil spring having the following particulars: Outer spring 1: mean coil diameter = 100 mm Wire diameter = 12.5 mm No. of turns = 15 Inner spring 2: mean coil diameter = 75 mm No. of turns = 20Both the springs are of equal initial length when unloaded. Ifthe working stress for each spring is to be same. The modulus of rigidity for the wire material is 80 GPa. Calculate the following:a. Diameter of steel wire for inner spring. b. Stiffness of inner springc. Stiffness of the compound spring. I need answer ASAP. Thank you!A helical compression spring has a scale of 400 lbs/inch, an inside diameter of 2.5 inches, a free length of 8 inches and with squared and ground ends. Material is to be chrome vanadium steel. For a load P of 750 lbs and for the average service Determine the standard size wire diameter Determine the number of active coils Determine the solid height Determine the stress at solid heightA helical compression spring with squared and ground ends has an outside diameter of 1.100 in, a wire diameter of 0.085 in, and a solid height of 0.563 in.Compute the ID, the mean diameter, the spring index, and the approximate number of coils.