Solve for the support reactions at A and B. W, = 400 #/FT. %3D w2=100#/FT A

Q: 10 kN-m 5 m 5 m

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Q: (d) MNkN/m 5@2m10m

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Q: Determine the vertical support reaction at point A.

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Q: Solve for the reactions and draw the shear and moment diagram. (7) MN kN-m 4m 6 m

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Q: %3D If the intensity of the distributed load acting on the beam is w = 3KN/m, determine the…

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Q: The resultant of the three forces is the force R = -170j kN acting through point B. Determine P1,…

A: Resultant of three force = R R=-170j^ kN tanθ=34cosθ=432+42=45sinθ=332+42=35∑M@B=0---(Clockwise…

Q: Determine the vertical reaction at D, A, force in FBC, and force in FGC

A: Consider the figure,

Q: Determine support reaction at A and B

A: Apply equilibrium : ∑FX=0∑FY=0∑M=0

Q: Determine the Reactions of the structure. Draw the Shear and Moment diagram Member BCDE only.  Let…

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Q: 07. The resultant of the three forces is the force R = -170j kN acting through point B. Determine P,…

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Q: Find the horizontal and vertical components of reactions at the pins A, B, and C.

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Q: so IN 30 AN/in D B. 2 m 2 m

A: Given data:

Q: . Determine the reactions at B, D and E then draw the shear and bending moment diagrams for the beam…

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Q: 1. Determine the horizontal reaction of the hinge support at A. (N) 2. Determine the vertical…

A: As per our guidelines we are supposed to answer only first three subparts of a multiple subpart…

Q: Determine the reactions at A, B and C. Support B s mm. Take E 200 GPa and I = 300 (106) mm4. 10 kN/m

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Q: PROBLEM 2: Solve for the reactions at C which is an internal pin. Roller support at D and pin…

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Q: Solve for the support reactions at A and B. 4 m W 15KN/m A B 3m 3m

A: ∑FY = 0 (Taking Upward +ve and Downward -ve) RA + RB - 15*4 = 0 RA + RB - 60= 0 RA + RB = 60…

Q: Determine the reactions at the fixed support at A and the roller at B. Support B settles 5 mm. Take…

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Q: Calculate the support reactions at A and C Calculate the internal force at D 8m 50 kN 10m

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Q: Solve for the reactions and draw the shear and moment diagram. (8) 4m MN kN/m + 6 m

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Q: Problem #2 Draw the necessary FBDS and solve for the external reactions (magnitude and direction) at…

A: Member BC: The following figure shows the Free Body Diagram of Member BC. The sum of moments of all…

Q: PROBLEM NO. 2 8 k/ft Determine the reactions at A and D. Assume the 15 ft supports at A and D are…

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Q: Determine support reaction at C

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Q: P, = 4.5kN W, = 2.4kN/m W2 = 1.6kN/m P2 = 3.6kN 2.1m 0.9m 1m 1.5m 1.5m 7m

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Q: 67 kN/m |A +一 8 m 4.0 m, B

A: Given beam- Members AB and BC  are joined by a hinge joint.

Q: The entrance of a warehouse has a roof that supports a roof load of 8 kN/m. The supports B and C are…

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Q: Determine the force P required to hold the 100-lb weight in equilibrium.

A: Consider pulley A and apply equation of equilibrium in y-axis:

Q: Solve for the reactions and draw the shear and moment diagram. 5 m MN KN 3m

A: Given data  MN = 98

Q: 450 N B 30 30 30 6.196 m 5.196 m 450N Treating horizontal reaction at A as redundant, what is the…

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Q: 15 kN/m Q2/ Determine the reactions at roller (A) and pin (C) for equilibrium of the member (ABC),…

A: ∑MC=0 VA×1.8 - 12×15×1.2×0.6+13×1.2 - 6×0.4 = 0 VA = 6.33 kN ↑

Q: Solve for the support reactions at A and B. W, = 400 #/FT. %3D w2=100#/FT A B 000 4'

A: Moment at A  = 0 RB(6+4) – 100(6)(6/2) – ½(300)(6)1/3(6) = 0 RB(10) – 3600 = 0 RB = 360

Q: 200kN 200kN A C ¿D E 3m 3m 3m 3m El= Constant a. Using the force method draw the primary structure…

A: Force method: The force method is used to analyze the statical indeterminate structures. The force…

Q: 4 kN/m 3m 3 m 3. Determine the support reactions at A and B.

A: Given beam is simply supported.The length of span,  L =6mThe uniform distributed load =4KN/m for 3m…

Q: 2. The beam ABC is built into the wall at C and supported by rollers at A and B. Compute the…

A: Given Propped cantilever beam with loading conditions and it is asked to compute the reactions at…

Q: Determine the vertical component of the reaction D, at the pin support D

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Q: 450 N B 30 30 30 6.196 m 5.196 m AEn N Treating horizontal reaction at A as redundant, what is the…

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Q: Compute for the support reactions and compute for all member forces.

A: By taking similar angles <AGF and <ACB, Side BC= 1.2×2.53.6 Side BC= 0.833 m  By taking…

Q: Solve for the reactions and draw the shear and moment diagram. (3) 5 m FN kN/m + 3 m

A: Given data  FN = 51

Q: Determine the reactions for the continuous beam shown by the three-moment equation. Draw the shear…

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Q: Solve for all the Support reactions. In dicote uni'ts & directions as well.

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Q: The resultant of the three forces is the force R = -170j kN acting through point B. Determine P1,…

A: GIVEN  R=-170 kn As resultant of p1,p2, and p3 is given R so we will try to convert p1,p2, and p3 in…

Q: 2 kN/m 10 kN-m 4 m 6 m 6 m 4 m

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Q: Solve for the following internal forces occurring on the beam loaded as shown below a. Moment at B…

A: Given-                                Here, a= 4.1 m, b=45.6 kN/m, c= 33.4 kN , d= 13.8 kN/m…

Q: P = 20.## kN M = 50.# kN-m W = 5.## kN/m A D F B E G 6 m 2 m 2 m 6 m 2 m

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Q: Determine the reactions at the beam shown:  Where  P = 15 kN  No=  22 kN.m  L1= 3.75 m L2 =4 m

A: Cantilever beams offer two reactions for vertical loads. Vertical Reaction at Fixed End. Moment…

Q: Determine the horizontal and vertical components of reaction at the pins A, B, and C.

A: GIven System  To find:  Horizontal and vertical components of reaction at the pins A, B, and C.

Q: Determine the vertical component of the reaction By at the pin support B 30 kN 50 kN to B D A 1 m 3…

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Q: اكتب اسمك والتوقيع على الورقة وتهمل اي اجابة بدون الاس و الرسومات الضرورية Draw the F.B.D. for the…

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Q: r the below structure a moment is applied at E, find the equilibrium moments exerted by e members on…

A: Given data  Different end support conditions viz hinged and fixed. Concentrated moment = 1000 kN-m…

Q: (7) 10 kN-m 4 m 6 m

A: Solution:- The given diagram is shown below,

Equilibrium and Support Reactions

Civil engineers deal with structures that are composed of several members connected or with individual members such as beams and columns. To analyze such structures, the condition of statics must be applied. Under the static condition, the members are considered to be in equilibrium under the action of forces, that is, the members are assumed to be having negligible velocity.