Solve for x.   a. x plus 2 and one half equals 3 and one fifth b. x minus 2 and two thirds equals five sixths

Q: 2. Solve for the value of x. 33 12 35 x+ 12

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Q: Solve for x. x+75 60° 50°

A: Solution:Given a circleLet the Arc AB=x+75To find xFormula:In a central angle∠AOB=arc AB

Q: Solve for the variable. 10. 21 4 25

A: To find: The value of x. Concept used: Pythagorean theorem: The square of the longest…

Q: Solve for X~ B(5,0.85), for r = 3. 0.024 0.138 O 0.583 0.225

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Q: Solve for x Solve for 0 37 11 5 4

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Q: Solve for x. Round to the nearest tenth. 37° 12 9.0 15.9 7.2 19.9

A: For the given angle θ = 37° Adjacent = 12 Opposite = x

Q: Solve for the value of x, round to the nearest tenth. 10.7 11.9

A: Use Pythagoras theorem and simple construction then simplify to get the result

Q: 4. Solve for the missing value. 14 12 8

A: Let the '?' be y. Since the three parallel inclined lines divide the other 2 lines in equal ratio,…

Q: Solve for x and y. 9. 10. 11. 75 140 to es

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Q: Solve for x to the nearest tenth. 10 3 13

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Q: Solve for x. 31° 24 X = (Round to the nearest hundredth.)

A: our objective is to solve for x.

Q: Solve for the variable. 33 6x+11 18 24 X =

A: Given, Three parallel lines cut two transversal line We have to find the value of x

Q: Solve for x to the nearest tenth. 3 Answer: 2.

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Q: 24 32 16

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Q: Solve for the value of x. 78°

A: Angles on straight line: The sum of angles that are formed on a straight line is equal to 180°

Q: Solve for æ: 6e? – 3 = 11

A: Given equation: 6ex-3=11 Add 3 to both sides. 6ex-3+3=11+36ex=14  Divide both sides by 6.…

Q: 4. 24 17 22

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Q: Solve for x. (7x – 1) 161° 65° O 15 0 7 12

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Q: Solve for x. 38 24 X= (Round to the nearest hundredth.)

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Q: Solve for x. Round to the nearest tenth. * (0/20 Points) 12 53° 7.2 9.6 15.9 16.8

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Q: 24 Set up an equation and solve for x. 18

A: Use the relation between chord and tangent of a circle.

Q: х - 12 1 18

A: Solving the problem by finding the value of x.

Q: Solve for the missing variable 45° 13/2

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Q: 1 Solve for x to the nearest hundredth: 5 = 98

A: logab = b×loga

Q: Solve for x. Round to the nearest tenths if n 3. 58° 22

A: Given data: The length of AC=22 and m∠B=58∘.

Q: 27 18 30

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Q: 20 60 50

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Q: Solve for x: 2x? + 26x + 80 = 0 O x= -8, -5 O x = - 5, 5 O x = - 16, -25 Ох326, 80

A: option first is correct  see below the answer and calculation

Q: 14 28

A: Follow next step

Q: Solve for x. 10 12 Answer: Submit Answer acer 2.

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Q: 18 12 20

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Q: Solve for x. 50 53 62° 80°

A: To determine value of x from the given figure.

Q: Solve for x to the nearest tenth. 7 10 6.

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Q: Solve for x. Round to the nearest tenth. 29 55° X =

A: we have to find the value of x from the given figure

Q: 13 Solve for x and Solve for y 86

A: Solve the following

Q: Solve for x. В 35° 27 X = (Round to the nearest hundredth.)

A: To find The value of x from the given right angled triangle

Q: solve for the variable. 7.5 = x + 1.25

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Q: 15° 33

A: Given : A right-angled triangle.

Q: Solve for x. Round to the nearest tenth. 25 x° 40

A: Given triangle - Then we have to find Value of x Since in the ∆ABC, ∠B be right angle  ∆ABC be…

Q: Solve for x. . ΔΑΒC - ADEC x + 1 AC 15 E B 12 x + 5

A: Given that: ∆ABC~∆DEC

Q: 32 2х 9.

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Q: Use the figure to solve for x when a 6 3. 4. 6. 8.

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Q: 10 a 450 600 b

A: Here I am attaching image so that you understand each and every step.

Q: 100 20 20

A: From the given figure, we find the value of x.

Q: Solve for x and y. Round to the neareast tenth. 12 50%

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Q: Solve for x. Round to the nearest tenth. 54 12

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Q: Solve for x. Round to the nearest tenth, if needed. 17. 5* – 3 = 100

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Q: Solve for x. 35° 48 X = (Round to the nearest hundredth.)

A: Given: To Find: Value of x. Concept: tanθ=PerpendicularBase=ACBC

Q: Solve for x. Round to the nearest tenth. 10 5 4

A: The figure is given by To evaluate : The value of x

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.