Solve for x

Q: log42(9x) = 2

A: Our Aim is to solve log x+2 (9x)=2 -(i)

Q: Solve the equation log2(log4x)=3 for x

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Q: Solve for . log2(x) + log2(x - 1) = 1

A: Given : log2x + log2x - 1 = 1

Q: Solve for x 3log 2 =log x

A: We have to find valu of x

Q: solve for x by converting the logarithmic equation to exponential form  log36(x)=1/2 x=

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Q: Solve for x: 1 loga = - 5 1024

A: Solve for x

Q: Solve for x by converting the logarithm equation log1\7 (x)=2 to exponential form.

A: We have the formula, loga(b)=m, then b=am

Q: solve log2 x-log2(x-1)=1

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Q: Solve for x log(4x)=log3+log(x-2)

A: We use the multiplication property of log From both sides log cancels

Q: Solve: log(x - 3) - log(x + 3) = log(x - 4)

A: To solve: The equation log x-3-logx+3=log x-4. Concept used: Logarithmic quotient rule: logab=log…

Q: solve : log(7x+2)=log(x-9)

A: Since both sides have log, so cancel log from both sides.

Q: solve for x log3(x+4)+log3(x-4)=2

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Q: Solve: log2 x + log2 (x - 4) = log2 (3x - 10).

A: To solve log2x+log2x-4=log23x-10

Q: Solve for the exact value of x. log2 (3æ) + 4 log2(4) = 2

A: Topic-logerthimic

Q: solve for x in log2 (x+3) + log2 (x-1) = log2 12

A: Givenlog2 (x+3) + log2 (x-1) = log2 12

Q: Solve for x.    (a) x2 − x = log5 25     (b) 3x + 5 = log2 64

A: Given:x2-x=log525 & 3x+5=log264To determine:Solution of given equations

Q: Solve for x. log 10 x=-2

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Q: Solve for x: log 4 (x² + 4x– 96)-log (x-8)=5 %3D

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Q: Solve for x by converting the logarithmic equation to the exponential form. log(x) = 4 x=_____

A: log10x=4⇒x=104⇒x=10000

Q: 5. Solve for x without using a calculator: log. (x) + log,(x – 16) = 2

A: The answer is found in step-2

Q: Solve for x in log3 (x- 7) + log3 (x + 4) = log3 26.

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Q: Solve for x by converting the logarithmic equation to exponential form. log (x) = 4 %3D

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Q: see attachment

A: Given logarithmic equation is,

Q: Solve for x.     (a) log3 x = −1     (b) log2 x = −4

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Q: Solve using law of logarithms: log3 (x+3) + log3 (2x - 3) = 1

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Q: 10) Solve for x. log5 x - log (x - 2) = log 2 |

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Q: Solve for x. log x = - 4 0.0001 -0.0001 1.386 -4

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Q: solve for x (use log where is necessary) 22+x=3x

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Q: log1 x = -4, X = ?

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Q: Solve for x: log2(x) + log2(x – 2) = 3 Solve for x: log:(x - 2) - log:(x - 4) = 2

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Q: Solve. log2(x-2) + log2(x+1) = 1

A: Given as

Q: log2 (4) =

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Q: Solve the equation for x. log27x+3  =3                                                        x

A: The given expression is

Q: Solve for x:  log381x - log3 32x = 3

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Q: Solve for x log (30x+20)- log(x)=2

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Q: Solve for x: log, (x? +8x - 20)-log, (x-2)=2

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Q: Solve for x: Log3(x-5)+Log3(x+3)=2

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Q: Solve for x. (a) log3 x + log3(x − 2) = 1    (b) log10(x + 3) − log10 x = 1

A: Part (a) Given expression is log3x+log3x-2=1

Q: Solve for x. log.x = log (r+ 8) – log2

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Q: Solve for x.   (a) log4 x = −2    (b) log5 x = 3

A: definition used: if y=ax then x=logay.   By using above definition, log4x=-2x=4-2x=116 Thus, the…

Q: Algebraically solve for x using log properties: log2 x + log2(x – 3) = 2.

A: The given equation is, log2x+log2x-3=2 As, logx is defined only for x>0, thus solution of this…

Q: Solve for x. log2(x) = 6   x=

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Q: Solve: Log (x + 3) Log (x - 2) + Log 2

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Q: Solve for x: log3 1,089 = 2 log3 x.

A: use the property of logarithmic property to find the value of x

Q: Solve for all values of x. log; (4x – 7) + log; (2x – 6) = 2 |

A: apply log formulas

Q: Solve for x in log4 (x+1) + log4 (x-1) = log4 15

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Q: Solve for x:

A: Given, logX2 =log16X

Q: Solve for x by converting the logarithmic equation to exponential form. log64(x) = X =

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Q: Solve for x: log2 (2) = - 1 %3D

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Q: log 10x=5 solve for x

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