Solve the Babylonian problem taken from a tablet found at Susa: Let the width of a rectangle measure a quarter less than the length Let 40 be the length of the diagonal. What are the length and width? Use false position beginning with the assumption that 1 (or 60) is the length of the rectangle A length 32, width9 B length = 40 viddh30 C. length = 32 widh D. length2 widt

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