Solve the equation 2x3 + 5x2 - 4x - 3 = 0 given that -3 is a zero of f(x) = 2x3 + 5x2 - 4x - 3.

Q: Solve the equation. x(x2-x-1)=(x2-2x)(x+1)-2x

A: Expand both sides and combine like terms.

Q: Solve the equation : 1/ (x2 - 3x + 2) = 1/(x + 2) + 5/(x2 - 4)

A:

Q: Solve the equation 2x3 - 5x2 + x + 2 = 0 given that 2 is a zero of f(x) = 2x3 - 5x2 + x + 2.

A: Given 2x3-5x2+x+2=0Giveh that 2 is a zero of fx=2x3-5x2+x+2Therefore x-2 is a factor  of given…

Q: Solve the equation 2r – 3x? - is a zero of f(x) = 2x3 - 3x – 11x + 6. 11x + 6 = 0 given that -2

A: Given that, the equation  2x3-3x2-11x+6=0  Given that,   -2 is a zero of f(x) = 2x3-3x2-11x+6 To…

Q: Solve equation.    2x/(x2 + 6x + 8)=x/(x + 4) -2/(x + 2)

A: Here given equation

Q: (a) Solve (b) Solve x²-3x x²-3x - 18 = 0. - 18 ≥ 0.

A:

Q: Show that the equation x3 - 15x + 1 = 0 has three solutions in the interval [-4, 4].

A: Using the Fundamental Theorem of Algebra: Any polynomial must have number of roots equal to the…

Q: Solve  equation. (x - 1)/(x - 2 )+x/(x - 3) =1/(x2 - 5x + 6)

A:

Q: X2-3X+3)3/2-1=0 Solve.

A:

Q: Solve the equation. 5x +8- (4x- [8(x– 1) – 2]} = 4(x – 3)

A: NOTE: Refresh your page if you can't see any equations. .

Q: Solve  A) 3x2+5x-2=0    B) (x-6)(x+3)=0

A: To solve the following parts,

Q: Solve f1x2 = x - 52x + 3; g1x2 = 3x + 51 - 2x

A: Consider the given function as fx=x-52x+3 and gx=3x+51-2x

Q: Solve the equation 3tan2 x - 9 = 0 on the interval [0, 2π).

A: The given equation is 3tan2 x - 9 = 0

Q: 2 + 2x-4 5 3 4. x+3 x-2

A: An expression become zero only if the numerator of the expression is zero. So to solve the given…

Q: Solve 4(a - 2x) = 5x +c/3for x.

A:

Q: Solve R1x2 = 2x - 6 x

A: given,          R(x)=2x-6

Q: -x3+8x2-2x-4 Solve for x

A: Given

Q: Solve f1x2 = 2x; g1x2 = 1 2 x

A: Given functions - f(x) = 2xg(x) = 1f∘g(x) = fg(x)f∘g(x) = 2g(x)f∘g(x) = 21f∘g(x) = 2

Q: 2. Solve for x, algebraically: -(x+ 5)(2x – 1)(x+ 2)

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Solve the equation x- 5x +2x + 8 = 0 given that 1 is a zero of f(x) = x° - 5x+2x + 8. 5x +2x +8.

A: Solution :-Given that -1 is a zero of f(x) = x3 - 5x2 + 2x + 8So, (x+1) must be factor of f(x)f(x) =…

Q: Solve the equation for x. (2 - 3x)5x + 4 . 5x = 0

A: To solve the equation: 2-3x5x+4·5x=0 Solution: Solving the given equation.…

Q: 2x (x-3)*

A: Here the given graph

Q: solve the equation for x 12x^3+5x^2-2x=0

A:

Q: Solve the equation √ 3(3x/3 · 3-2x ) / 3-x = 9 for x.

A: Given that 33x3·3-2x3-x=9. Solve for x as follows.…

Q: Solve for x. (3x - 63) A - C. (2x + 2)

A: We have to find x

Q: Solve: x* + 2r³ – x² – 4x – 2 = 0.

A: x4+2x3-x2-4x-2=0

Q: how do you solve this equation:              2x+1f(x+1)= ------              3x-5

A: We have to solve equation for f(x),where f(x+1) is given by:

Q: solve polynomial equation  1) x^3+2x^2-25x-50=0 2) x^4-6x^3-9x^2+14x=0

A: To solve the given polynomial equations

Q: solve using first principle f(x)=2x2-x

A: The first principle of derivative is : We will plug the given function in it to find f'(x).

Q: Solve the equation x3 - 9x2 + 26x - 24 = 0 given that 4 is a zero of f(x) = x3 - 9x2 + 26x - 24.

A: Given: fx=x3-9x2+26x-24 if x=4 is a zero of given function then given function will be…

Q: Solve the rational equation. 3/X2+2X-8  -  1/X2+9X+20  =  6/X2+3X-10

A: Given equation is: 3x2+2x-8-1x2+9x+20=6x2+3x-10 To find the value of x.

Q: Solve. 2x X-4 x+2 x+2

A:

Q: Solve the equation. 7x+1 -4 2. x-2 x x-2x

A:

Q: Find the real solutions of equation x4+4x3+2x2-x+6=0

A: To determine the real solutions of given equation.

Q: Solve.  A) x2-4x-5=0   B) 3x2-5x-2)=0

A:

Q: Differentiate f(x) = [(3x4 – 5)(2x³ + 9x – 6)]3 and solve for f'(2).

A:

Q: Find all real solutions of the equation.

A: Given equation,  x-9-3x=0.   It is simplified as follows: x-9-3x=0 Squaring both sides,…

Q: Solve : 3/(x - 3) + 5/(x - 4) = x2 - 20/(x2 - 7x + 12)

A: To solve the given equation

Q: solve algebraically y=x^2-6x+7 and y=-4x+22

A:

Q: Solve the equation x3 – 13x2 + 47x - 35 = 0 given that 1 is a zero of f(x) = x° – 13x2 + 47x - 35.

A: The given equation is x3-13x2+47x-35=0, 1 is a zero of f(x)=x3-13x2+47x-35

Q: Solve : 2x/(x - 3) + 6/(x + 3) = - 28 / (x2 - 9)

A: Given:2xx-3 + 6x+3 =-28x2-9

Q: How would I solve for x? 8 - 4x = 3x2 - 6x + 2

A:

Q: 2) Solve for x. 15x - 4(2x - 1)= 20

A: Use basic arithmetic operations.

Q: Solve for the value of x:  √2x+5 - √x+3=2

A: Given:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.