Solve the equation for exact solutions over the interval [0, 2n]. sin3x = -1 Select one: O a. 2x 4 13 3 3 57 3 O b. {0, 5. 5. * *. ,} 37T 37 7T 4 2 4 11T 13T 23 12 12 12 12 {55.} {i #} O d. I 7 11 3 e. 12

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A: The given equation,    -cos2x-sin2x=1 on the interval 0≤x≤2π

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A: We have to find the solution

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A: use the trigonometric ratio value for evaluating the value.

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A: Given equation: 2 sin θ+4=3

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A: We have to find t

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A: We can solve the question as per the criteria and conditions given.   NOTE :: As per our guidelines…

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A: The given equation is 2tan2x-3secx=0 and the given interval is [0,2π)

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A: use trigonometric table to find the angle.

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Q: 10. Solve for t on the interval [0, 2π) (a) 2 cos² t-cost-1=0 (b) 2 sin²t-3 sint + 1 = 0 taol al (c)…

A: Given

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Q: Find the solution in the interval from 0 ≤ θ < 2π 2sin2 x - cosx -1 = 0

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A: General equation of tanθ = tanα is   θ = nπ + α.   where n = 0 , ±1,±2,±3,................

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A: we have to find the solution

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Q: Find LT of (i) e-*(2 cos 5t – 3 sin 5t) (ii) e²ª cos² t (iii) e“ sin 2t cos t ,4t

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