Solve the equation on the interval [0, 27). 15) cos 2x = 2
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A: cos(-x) = cos(x) cosπ2-x = sin(x)
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A: Given,
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A: As we know that Sinx-y=SinxCosy-CosxSinyThe genaral solution of Sinz=-1 then z=Sin-1-1=nπ±π2
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A: Solution of given question is written in below steps.
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A: Since you have posted multiple questions, we will solve only first question for you. To getremaining…
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