Solve the equation y' + y · tan (x) = sec(x) Ans y sec(x) = tan(x)+c %3D

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A: Integration by parts:∫u(x)v(x)dx=u(x)∫v(x)dx-∫du(x)dx∫v(x)dx

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A: Given that Third order diffrancial equationy3+2y''-y'-2y=0,  y0=8,y'0=10,y''0=0Solution :y3+2y''-y'-...

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