Solve the Excel Sheet attached with this question ADEFGH1PART C: Q.2 SOLVE THE FOLLOWING QUESTION2 Size3 Large4 LargeColorCurrentOrdered Received QtySum of order quantities greater than 35Green4825-Apr05-May35Sum of order quantities 35 or lessPurple1808-Apr18-Аpr20Sum of all order quantities except 355 Large6 Large7 Large8 Large9 Medium White10 Medium Black11 Medium Blue12 Medium PurpleWhite1308-May40Black6325-Apr05-May45Blue08-May15-Apr1240Red5725-Apr351608-Apr18-Apr501908-Apr18-Аpr5025-Apr01-May08-May08-Apr15-Apr25-Аpr3205-May354211-May3013 MediumGreen93514 Medium Red4418-Apr25-Apr4015 SmallPurple594016 SmallWhite4505-May5017 SmallRed3215-Apr4018 Small19 SmallBlack1525-Apr5025-Apr25-AprGreen4115-Аpr4520 SmallBlue3915-Apr40B.

Answered: Image /qna-images/answer/48f5c5e6-7125-4da5-be74-6ce3d45eb560.jpg

Answered: В D H. PART C:Q.2 SOLVE THE FOLLOWING…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Correct answer will upvoted else downvoted. segment of place where there is length n there are k climate control systems: the I-th climate control system is set in cell artificial intelligence (1≤ai≤n). At least two climate control systems can't be put in a similar cell (for example all man-made intelligence are particular). Each climate control system is characterized by one boundary: temperature. The I-th climate control system is set to the temperature ti. Illustration of portion of length n=6, where k=2, a=[2,5] and t=[14,16]. For every cell I (1≤i≤n) discover it's temperature, that can be determined by the equation min1≤j≤k(tj+|aj−i|), where |aj−i| means outright worth of the distinction aj−i. As such, the temperature in cell I is equivalent to the base among the temperatures of forced air systems, expanded by the separation from it to the cell I. How about we take a gander at a model. Consider that n=6,k=2, the main forced air system is put in cell a1=2 and…
Suppose you want to solve the following equality 2a + b + 3c + 4d + 6e = 45 What is the chromosome phenotype? What is the fitness function? What is the fitness value of a, b, c, d, e = (The first five numbers of university ID)? (hint if ID= 437818854 then a=1, b=8, c=8, d=5, e=4)
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1. The Fibonacci numbers F(0), F(1), F(2), are defined by the recurrence relation:F(0) = 0,F(1) = 1,F(n) = F(n-1) + F(n-2) for n >= (greater than or equal to) 2.The first few Fibonacci numbers are 0, 1, 1, 2, 3, 5, 8, 13, and 21. Prove by induction that for all n >= (greater than or equal to) 1.[F(n-1)][F(n+1)] - F(n)2 = (-1)n.Hint: Express F(n-1) in terms of F(n)and F(n-2) and express F(n+1) in terms of F(n) and F(n-1). Expand and simplify, then apply the inductive hypothesis. Handwritten only
True or False 1. If b|a we say that b is a divisor of a. Multiple choice 1. The congruence relation is used to define ------. Short Answer 2. ------- have the following properties: 1. a=b(mod n) if n|(a-b) 2. a=b(mod n)implies b =a(mod n) 3. a=b(modn) and b = c(mod n) imply a=c(mod n)
Put these order of growth functions in order from most efficient to least efficient: n3, 2n, nlogn, n5, 1, n2 A. n3, 2n, nlogn, n5, 1, n2B. 1, n2, nlogn, n3, n5, 2n C. 1, nlogn, n2, n3, n5, 2nD. 1, nlogn, n2, n3, 2n, n5
Show that the relation R consisting of all pairs (x, y) suchthat x and y are bit strings of length three or more thatagree except perhaps in their first three bits is an equivalence relation on the set of all bit strings of length threeor more.
A subsequence of a sequence is obtained by deleting zero or more values in the sequence. For example, acdfh is a subsequence of abcdefghi. The order must be preserved. The longest common subsequence problem takes two strings as input and outputs the length of the longest string that is a subsequence of both input strings. Describe an efficient dynamic programming algorithm for the longest common subsequence problem. Start by writing recursive equations using the shop around principle. Concentrate on the last values in the input strings. If they are the same, keep them and look for a longest common subsequence of the two strings with their last characters removed. If the last two characters are different, you can only keep one of them. Try keeping one, and throwing the other one away. Then keep the other one. Take a maximum, since you are looking for a longest common subsequence. Then implement the equations using memoization.
f(n) = n3 - (n2 log2 n) + 2n f(n) ∈ O(n3) by giving the constants (c, n0) and arguing that your constants hold as n goes to infinity by either "chaining up", "chaining down", carefully treating the inequality as an equality and doing some algebra, or even weak induction. Also, what is the minimum value for c (in the definition of O() ) forj this problem and is it an exclusive or inclusive minimum/bound.
Mattlan ataach screenshot of graph. Gen ate sets of information (xi, Yi) utilizing = (0 : 0.1 : 2.5)';y=erf(x); in MATLAB. Expect that the result y(t) can be approximated by a 6th - th degree polynomial as far as x(t) (counting a consistent predisposition term, so seven dad rameters altogether): _y(t) = 0₁ + 0₂x(1) + 03x² (1) + 04x³ (1) + 05xª (1) + 0x³ (1) + 07xº (1) Settle for the coefficients 0₁, I = 1,2,3,4,5,6,7 utilizing clump least squares. Com-pare the outcome with the MATLAR capability "polyfit.".
Interchange Base Points AlgorithmOutput: a base B = [131,132..... 13j-1, 13L.+1, 13j, 13j+2, 13j+3..... 13k] for G; a strong generating set relative to B; procedure interchange(var B: sequence of points; vat S: set of elements; j: 1..k-1);Interchange Base Points AlgorithmInput: a group G; a base [131,132..... 13k] for G and a strong generating set; an integer j between 1 and k-l; Output: a base [131,132..... 13k] for G and a strong generating set.
Applying the banker’s algorithm, which of the following would be a possible order of completion for the following state? Available = (4, 4, 1, 1) Allocation Max ABCD ABCD T0 1202 4316 T1 0112 2424 T2 1240 3651 T3 1201 2623 T4 1001 3112

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