Solve the following problems. Show your complete solutions and final answers. Expecting to know the ff: solution for z-value/s, normal curve graph, solution for probability, and final answer. According to a study, the average number of hours of TV viewing per household per week in the Canada is 20.8 hours and the standard deviation is 18.2 hours. If a sample of 99 households is taken, what is the probability that: (a) the sample average is more than 24 hours? (b) the sample average is less than 17 hours? (c) the sample average is between 15 and 25 hours?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 23PFA
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Solve the following problems. Show your complete solutions and final answers.
Expecting to know the ff: solution for z-value/s, normal curve graph, solution for probability, and final answer.
According to a study, the average number of hours of TV viewing per household per week in the Canada is 20.8 hours
and the standard deviation is 18.2 hours. If a sample of 99 households is taken, what is the probability that:
(a) the sample average is more than 24 hours?
(b) the sample average is less than 17 hours?
(c) the sample average is between 15 and 25 hours?
(Hint: Recall that average is synonymous with mean.)
Transcribed Image Text:Solve the following problems. Show your complete solutions and final answers. Expecting to know the ff: solution for z-value/s, normal curve graph, solution for probability, and final answer. According to a study, the average number of hours of TV viewing per household per week in the Canada is 20.8 hours and the standard deviation is 18.2 hours. If a sample of 99 households is taken, what is the probability that: (a) the sample average is more than 24 hours? (b) the sample average is less than 17 hours? (c) the sample average is between 15 and 25 hours? (Hint: Recall that average is synonymous with mean.)
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