Solve the system. If there is no solution or if there are infinitely many solutions and the system's equations are dependent, so state= 35x+ YX + y- z = 182x + 5y + Z 0Select the correct choice below and fill in any answer boxes within your choiceOA. There is one solution. The solution set is { 02(Simplify your answers.)O B. There are infinitely many solutionsO c. There is no solution.Click to select and enter your answer(s) and then click Check AnswerClear AlAll parts showingThis course College Aigebra Section 80056 is besed on Bitaer College Algeora ith integrated Review, Tenere to searchHEWL ETT PACK ARDfe16t4I0&$4O563

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Asked Jul 23, 2019
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Solve the system. If there is no solution or if there are infinitely many solutions and the system's equations are dependent, so state
= 3
5x+ Y
X + y- z = 18
2x + 5y + Z 0
Select the correct choice below and fill in any answer boxes within your choice
OA. There is one solution. The solution set is { 02
(Simplify your answers.)
O B. There are infinitely many solutions
O c. There is no solution.
Click to select and enter your answer(s) and then click Check Answer
Clear Al
All parts showing
This course College Aigebra Section 80056 is besed on Bitaer College Algeora ith integrated Review, Te
nere to search
HEWL ETT PACK ARD
fe
16
t4
I0
&
$
4
O
5
6
3
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Solve the system. If there is no solution or if there are infinitely many solutions and the system's equations are dependent, so state = 3 5x+ Y X + y- z = 18 2x + 5y + Z 0 Select the correct choice below and fill in any answer boxes within your choice OA. There is one solution. The solution set is { 02 (Simplify your answers.) O B. There are infinitely many solutions O c. There is no solution. Click to select and enter your answer(s) and then click Check Answer Clear Al All parts showing This course College Aigebra Section 80056 is besed on Bitaer College Algeora ith integrated Review, Te nere to search HEWL ETT PACK ARD fe 16 t4 I0 & $ 4 O 5 6 3

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Expert Answer

Step 1

The given system of equations are,

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[5x + y = 3 x+y-=18 2.x+5y + = 0 Write the system of linear equation in matrix form AX = B as follows. [5 1 3 0 1 -1 || y |= | 18 1 2 5 1 0

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Step 2

Now, convert the augmented matrix into row echelon form.

First, interchange the Rows 1 and 2.

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[18 1 1 -1 5 1 0 3 y 2 5 1 0 Multiply Row 1 by -5 and add the result to the second row. 1 1 -1 18 -87 -4 5 y 2 5 1 0 Multiply Row 1 by -2 and add the result to the third row -1 1 1 18 -87 0 -4 5 y 10 3 3 -36 Interchange the Rows 2 and 3. EH -1x 1 1 18 0 3 3 -36 y 0 -4 5 -87

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Step 3

Multiply Row 2 by 4/3 and add the...

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1 1 1 18 0 3 3 -36 y -135 0 0 9 Divide Row 3 by 9 and Row 2 by 3. 1 1 18 0 1 1 -12 y 0 0 1 -15 Multiply Row 3 by -1 and add the result to the second row. 1 1 18 0 1 0 3 y 0 0 1 -15

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