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Solve using Gaussian Elimination with back-substitution or Gauss Jordan 000 = 80을 + 20승 - 1루 * - = 8x 올 - x음 + 12층 1²1 - 1²2 + 1²3 = 130 i = x 6 음 - - 2x 6 2 = Tx O ○ x1 = 21, 22 = -1, 03 = -1 X3 ○ x1 = 1, x2 = -1, x3 = 1 X2 0x₁=1, x2 = -1, 23 = 1/ 3' X2 3

Solve using Gaussian Elimination with back-substitution or Gauss Jordan 000 = 80을 + 20승 - 1루 * - = 8x 올 - x음 + 12층 1²1 - 1²2 + 1²3 = 130 i = x 6 음 - - 2x 6 2 = Tx O ○ x1 = 21, 22 = -1, 03 = -1 X3 ○ x1 = 1, x2 = -1, x3 = 1 X2 0x₁=1, x2 = -1, 23 = 1/ 3' X2 3

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.2: Guassian Elimination And Matrix Methods
Problem 84E: Explain the differences between Gaussian elimination and Gauss-Jordan elimination.
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Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 x1 - x2 + x3 630 121 + 102 - 2003 x₁ - x2 + x3 = 1500 139 O x1 x₁ = 1², x₂ = − 1², x3 = // X2 0 x₁ = 1,₂ = -², x3 = -1/ 59 4 0 x₁ = 1, ₁₂ = -1, x3 = 1/ X3 4 0 x₁=1, x₂ = − 1, 23 = 1/ www - 3, X2 3 Next ▸ 12 25 || || 19 45
Transcribed Image Text:Solve using Gaussian Elimination with back-substitution or Gauss Jordan 349 x1 - x2 + x3 630 121 + 102 - 2003 x₁ - x2 + x3 = 1500 139 O x1 x₁ = 1², x₂ = − 1², x3 = // X2 0 x₁ = 1,₂ = -², x3 = -1/ 59 4 0 x₁ = 1, ₁₂ = -1, x3 = 1/ X3 4 0 x₁=1, x₂ = − 1, 23 = 1/ www - 3, X2 3 Next ▸ 12 25 || || 19 45
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