Solving Equation 5 for a in terms of the measured quantities x and t gives 2x (Eq. 6) a = t2
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A: Given, t1 = 9 mins. and t2 = 7 mins.
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Q: ᴅᴇꜰɪɴᴇ ᴡʜᴀᴛ ɪꜱ ʙᴇʀɴᴏᴜʟʟɪ'ꜱ ᴇQᴜᴀᴛɪᴏɴ. and ɢɪᴠᴇ ᴀᴛ ʟᴇᴀꜱᴛ 5 ᴘʀᴏʙʟᴇᴍ ᴡɪᴛʜ ꜱᴏʟᴜᴛɪᴏɴꜱ
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Q: ᴅᴇᴛᴇʀeᴍɪɴᴇ ᴛʜᴇ ᴜɴɪᴠᴇʀꜱᴀʟ ꜱᴀʏʙᴏʟᴛ ᴠɪꜱᴄᴏꜱɪᴛʏ ᴏꜰ ᴡᴀᴛᴇʀ ᴀᴛ ᴛ=3ꜱ. ᴄᴏɴᴠᴇʀᴛ ᴛʜᴇ ᴀɴꜱᴡᴇʀ ᴛᴏ ᴘᴏɪꜱᴇꜱ
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A: p= -560N
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Q: ᴀɴ ᴏᴘᴇɴ ᴄʏʟɪɴᴅʀɪᴄᴀʟ ᴠᴇꜱꜱᴇʟ 1.2 ᴍ ɪɴ ᴅɪᴀᴍᴇᴛᴇʀ ᴀɴᴅ 2.1 ᴍ ɪɴ ʜᴇɪɢʜᴛ ɪꜱ ꜰɪʟʟᴇᴅ ᴜᴘ ᴡɪᴛʜ ᴡᴀᴛᴇʀ ᴛᴏ 2/3 ᴏꜰ…
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Q: For the given figure shown, a - 6 m, b = 9 m, c= 3 m, r= 7m. h b
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Q: 40. Find the magnitude of the torque about P if a 36-lb force is applied as shown. 4 ft PE 4 ft 30°…
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Q: x-6 if x-3 Q:2/ determine if the function: f(x) = { 2 if x = 0 V4 +x² if x>0 Is continuous at x 0
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Q: Determine the range of values of v for which both wires remain taut. Where x1 is the last digit of…
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Q: Consider the following statements: A. The weight of a body produces a tendency to rotate. B. The…
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Attached question 5, along with equation 6.
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- Given values: m1 = 10kg, r1=75 cm, m3=20kg, r3=25cm, m4=5kg, had to find the value of r4=? I got r4=50cm m1 = 10 kg at r1 = 75cm m3 = 20 kg at r3 = 25cm m4 = 5 kg at r4 = 50cm 1. Compute the theoretical value of r3 using the following equation: r1m1 = r3m3 + r4m4 2. Compute the % error of r3 using the following equation: % error = |theoretical value - experimental value| / theoretical value x 100%A 45 grams (0.045 kg) golf ball of diameter equal to 43 mm fell into a 2m deep lake. Neglect inertia at the moment of impact. Assume viscosity of 1.12x10-3 Ns/m2 , water density of 1,000 kg/m3 and Cd=0.5. Sphere volume equals 4π r³ /3. 1. How long will it take from the moment it hits the surface until it gets to the bottom? 2. If one estimates the Cd with Cd=24/Re formula, the settling velocity would be unrealistically large. Why?Determine the blade length for a wind turbine that supplies an electrical power output of 1.95 MW and given the following parameters: Wind speed = 51 km/hr The gear, generator and electric efficiencies are 93%, 95% and 91% respectively. The power coefficient of the wind turbine is the maximum possible as given by the Lanchester-Betz limit. Assume the atmospheric air conditions are 1.01325 bar and 27 °C
- The turning moment diagram for a petrol engine is drawn to the following scales: turning moment 1 mm to 2·5 Nm; crank angle, 1 mm to 1°. The fluctuations of energy between the crank positions for minimum and maximum speeds corresponds to an area of 600 mm² of the turning moment diagram. The flywheel is made from cast iron, of density 7·2 tonnes/m3. Determine: (a) The greatest fluctuation of energy (b) The mass of the flywheel required to prevent the a fluctuation of speed greater than ± 0·5% from the mean speed of 1600 rev/min if the radius of gyration is 120 mm. (c) The dimensions of the flywheel (diameter and thickness) (d) Describe the possible consequences to the system if the flywheel was not used to limit the fluctuation of speed.The figure shown below is released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. For the values given below answer the following questions:Position 1 is Ha1 μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the Gravitational Potential Energy for mass mA at position 1 (remember your signs)? What is the Gravitational Potential at position 1 for mB? What is the Potential Energy of the spring at position 1? What is the Kinetic Energy at position 1 for mA? What is the Kinetic Energy at position 1 for mB? Again we have the figure shown below that was released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. At position 2 the spring is at its max stretch. Remember we have the values below; answer the following questions: μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the max stretch in the spring?The shaft of a turbine rotor, initially at rest, accelerates uniformly for 0.9s at 25 rad/s2. Compute and identify the nearest value of the angle turned through by the shaft in degrees during this time. a. 960o b. 580o c. 645o d. 720o Clear my choice
- Two boxes of masses m and M are moving on a horizontal rough plane and are in contact to each other. The 2 dynamic friction coefficients are µkm and µKM respectively. A horizontal force F is applied to M, on the side opposite to that one in contact with m, which pushes M against m. Apply the basic concepts of dynamics and to draw the free body diagram of the boxes and find the value of their acceleration. The given data is as follows: m=1 [kg] M=5 [kg] F=670N µkm=0.4 µkM=0.45This most likely is made to be a probelm about mx''+bx'+kx=f(t) m = mass b = friction k = spring constant 4. A mass weighing four pounds stretches a spring 24 in. Suppose the mass is atequilibrium and is set into motion with a velocity of 6 inches per second. The mass is in a mediumwhere friction is small, and we assume it is zero. Note that the acceleration due to gravity near theearth’s surface where the experiment takes place can be taken as 32 ft/s2.(a) Suppose that in addition to the conditions described above, a hammer strikes the mass everyπ/2 seconds starting at t = 0. A delta function with impulse of 1 pound-second models theforce of each blow to the mass. Find the function x(t) for the displacement from equilibrium infeet of the mass at time t in seconds. Express x(t) as a piecewise defined function without the use ofunit step or Heaviside functions and such that in each time window it is a different multiple of the samesinusoidal function.(b) Now assume the same spring-mass…A 16-cm x 20-cm gas engine has a normal speed of 450 rpm. Determine a.) the speed, in rev/s and rad/s; b.) the linear velocity of the crank pin, in cm/s and m/s. If the engine is allowed to stop at a uniform rate in 3 minutes and 20 seconds, determine c.) the deceleration of the crank, in rad/s²; d.) the distance, in cm, traveled by the crankpin in coming to rest; and e.) the distance, in cm, traveled by the piston in coming to rest.
- given:Q2A=12 INCHESAB= 2FT 4 INCHESBC= 8 INCHESDE = 1 FT 3 INCHESQ7E= 12 INCHESQ5C= 2 FTDF= 2 FTCE = 3FT Ks -> use appropriate scaleKv -> 400ft/min= 1 inchVa= 472 ft/ min ☆ Solve the velocities of F and E by Resolution and Composition☆ pls show the output....A steam engine develops power at mean torque of 19,000 N-m and velocity of 10 m/s. The mean diameter of the flywheel rim is 1.2 meters. The coefficient of fluctuation of speed is 0.03 and the coefficient of fluctuation of energy is 0.21. Determine the thickness of the rim in mm if the width of the rim is twice of its thickness. Assume density of rim material as 7250 kg/m3.Assume the following objects are pushed with a force such that they all accelerate at the same rate of 150 meters per second squared [ m / s 2. Determine which object requires the greatest force to accelerate at this rate. Cricket ball , mass = 0.35 pound - mass [ lb m ] Hockey puck , mass = 17 decagrams [ dag ] Soccer ball , mass = 4000 decigrams [ dg ] Rugby ball , mass = 0.031 slu