Specific Heat:    Find Ccu MCu* CCu*(Ti-Cu - Tf)=MAl*CAl*(Tf - Ti-Al)+ Mw *Cw*(Tf-Ti-w) MCu= 379.8 kg; Ti-Cu= 100 degrees Celcius; Tf= 32 degrees Celcius;  MAl= 46.4; CAl= 0.22; Tf-Al = 32 degrees celcius; Ti-Al= 20 degrees celcius; Mw=168.2; Cw=1.00

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter11: Energy In Thermal Processes
Section: Chapter Questions
Problem 33P: A high-end gas stove usually has at least one burner rated at 14 000 Btu/h. (a) If you place a...
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Specific Heat: 

 

Find Ccu

MCu* CCu*(Ti-Cu - Tf)=MAl*CAl*(T- Ti-Al)+ Mw *Cw*(Tf-Ti-w)

MCu= 379.8 kg; Ti-Cu= 100 degrees Celcius; Tf= 32 degrees Celcius;  MAl= 46.4; CAl= 0.22; Tf-Al = 32 degrees celcius; Ti-Al= 20 degrees celcius; Mw=168.2; Cw=1.00

 

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