Specific Volume The ratio of total volume of air to its mass. RaTa να-Vα РaVa RaTa RaTa V = m Ра (Pt – Pv) Where: v = specific volume, m³ /kga.a 3 m = mass of dry air, kg partial pressure of dry air (Pt – Pv), kPaa Ta = absolute dry air temperature,°K Ра — Ra = gas constant of dry air, kJ /kg°K 0.28708 kJ /kg°K =

Specific Volume The ratio of total volume of air to its mass. RaTa να-Vα РaVa RaTa RaTa V = m Ра (Pt – Pv) Where: v = specific volume, m³ /kga.a 3 m = mass of dry air, kg partial pressure of dry air (Pt – Pv), kPaa Ta = absolute dry air temperature,°K Ра — Ra = gas constant of dry air, kJ /kg°K 0.28708 kJ /kg°K =

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter2: Matter And Energy

Section: Chapter Questions

Problem 29RQ: If 3000 ft3 of air is crossing an evaporator coil and iscooled from 75F to 55F, what would be the...

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Problem 3: A large room contains a volume of air of Va = 11 m3 at a temperature of Ta = 55° F. It also contains a bathtub holding a volume of water of Vw = 0.51 m3 at a temperature of Tw = 111° F. Parts (a), (b), (c) are already complete. Just need parts (d) and (e). Part (a) If the density of the air at Ta is ρa = 1.25 kg/m3, calculate the mass of air in the room in kilograms. ma = 13.75 Part (b) If the density of the water at Tw is ρw = 1000 kg/m3, calculate the mass of the water in the bathtub in kilograms. mw = 510 Part (c) Take the room and water as an isolated system. Write an equation for the equilibrium temperature of the system T in terms of ma, Ta, mw, Tw, and the specific heat capacity of the air ca and the water cw. T = ( mw cw Tw + ma ca Ta )/( mw cw + ma ca ) Part (d) Calculate the final temperature of the system in kelvin, assuming a constant specific heat for the water of cw = 4180 J/kg⋅K and a constant specific heat capacity for the air of ca = 1010 J/kg⋅K.…
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