ssohs/3026619/variants/3026619/take/12/ = Governor's Next Generation Commis... >O O< Step 1 2 3 4 5 6 7 Explanation Assign the oxidation number. Split equation into two half- reactions. Identify the oxidized and reduced species. Balance atoms that are not hydrogen or oxygen. Compute electrons lost and gained. Complete the reaction. Check your work. DISMISS Show My Work On the left-hand side, Al is 0, S is +6, and O is -2. On the right-hand side, Al is +3, S is +6, O is -2, and H is +1. Al(s) →Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g) Al was oxidized. H₂SO4 was reduced. You need 2 Al(s) on the left-hand side, and you need 3H₂SO4(aq) also on the left-hand side. 3 electrons lost in oxidation 1 electron gained in reduction You need 3H2(g). This gives 2Al(s) + 3H₂SO4(aq) → Al2(SO4)3(aq) + H2(g)- The aluminum reaction lost 3 electrons and there is one instance of that. The sulfuric acid (H₂SO4) reaction gained 1 electron and there are 3 instances of that. It is balanced. All Changes Saved Continue
ssohs/3026619/variants/3026619/take/12/ = Governor's Next Generation Commis... >O O< Step 1 2 3 4 5 6 7 Explanation Assign the oxidation number. Split equation into two half- reactions. Identify the oxidized and reduced species. Balance atoms that are not hydrogen or oxygen. Compute electrons lost and gained. Complete the reaction. Check your work. DISMISS Show My Work On the left-hand side, Al is 0, S is +6, and O is -2. On the right-hand side, Al is +3, S is +6, O is -2, and H is +1. Al(s) →Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g) Al was oxidized. H₂SO4 was reduced. You need 2 Al(s) on the left-hand side, and you need 3H₂SO4(aq) also on the left-hand side. 3 electrons lost in oxidation 1 electron gained in reduction You need 3H2(g). This gives 2Al(s) + 3H₂SO4(aq) → Al2(SO4)3(aq) + H2(g)- The aluminum reaction lost 3 electrons and there is one instance of that. The sulfuric acid (H₂SO4) reaction gained 1 electron and there are 3 instances of that. It is balanced. All Changes Saved Continue
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 11QAP: When one mol of KOH is neutralized by sulfuric acid, q=56 kJ. (This is called the heat of...
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