Stack Segment and Extra Segment Register Control Flag Register and Conditional Flag Register Logical Address and Physical Address Minimum Mode and Maximum Mode of 8086 Micrprocessor iv NMI & INTR
Q: 243. Fetching an instruction is: a) Bringing the instruction from stack to the microprocessor. )…
A: Q 43. Fetching an instruction is: a) Bringing the instruction from stack to the microprocessor. b)…
Q: * data can be directly loaded from address into register using direct addressing mode O register…
A: Here, we are going to identify the addressing mode which will load the register directly from…
Q: 11. The return address from the interrupt-service routine is stored on the a. System heap b.…
A: Given that, 11. The return address from the interrupt-service routine is stored on thea. System…
Q: * addressing mode consists of instruction code only ... .. direct addressing mode O indirect…
A: The solution to the given problem is below.
Q: The --is a 16-bit register sometimes referred to as the status .register Address register O Stack…
A: The answer is...
Q: The 8086 data bus consists of 8, 16, or 32 parallel signal lines * 8, 16, or 32 parallel signal…
A: Below is the answer to above question. I hope this will be helpful for you...
Q: Design 64K * 21 bit Computer. Adresss (0-15) opcode (16 - 19) addressing mode (20) - Direct/Indirect
A: Addressing Modes Addressing Modes The term addressing modes refers to the way in which the operand…
Q: The instruction " DEC R1 “ is: O A. Three - address instruction O B. One - address instruction O C.…
A: DEC R1: DEC Decrements the value of register by 1. If Initial value of register is 0, decrementing…
Q: Instruction fetching stage begins with elect one: a.Memory Address Register b.Instruction Decoder…
A: Correct option: Operand Register
Q: CPU Main Memory Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache A simple processor…
A: Answer: I have given answered in the handwritten format in brief explanation
Q: (True/False): The x86-64 instruction set is backward-compatible with the x86 instruction set
A: x86-64 instruction set x86-64 instruction set is the 64-bit version of the x86 instruction set. It…
Q: 8. Performance of microprocessor is measured in what is called million instructions they can execute…
A: 8 ) Clock Speed 9) Destination Index(DI) 10) Register Indirect Mode
Q: A computer with a 32 bit word uses an instruction format that includes direct and indirect…
A: A computer with a 32 bit word uses an instruction format that includes direct and indirect…
Q: H.W. an instruction is stored al location 300 with its address field al location 301. The address…
A: Step 1 The answer is given in the below step
Q: In a single cycle processor, the clock period is constrained by the instruction taking the shortest…
A: False It is just Length
Q: MOV CX,223 * Register indirect addressing mode Immediate addressing mode Based relative addressing…
A: Register addressing mode MOV CX 223 copies the contents of the 223 into the CX register
Q: Q/ Design the basic interface for 8486 Microprocessor. Hint : Address and Data multiplex or not ?
A: I have answer this question in step 2.
Q: Please describe ISA (Instruction Set Architecture), R-type, J-type, and L-type instructions…
A: An instruction set architecture (ISA) is a computer science term that refers to an abstract model of…
Q: Design a 8086 memory system consisting of 1 MB , using 128 k * 8 memory
A: Solution:-
Q: 8086 Microprocessor is having 20-bits data bus and 16-bit Address bus Select one: O True False
A: the above is false
Q: Q3. Mark True or False, correct when false: a) Address bus is bidirectional b) Data bus is…
A: NOTE: As per our guidelines we are supposed to answer only one question. Kindly repost other…
Q: Describe a single memory architecture.
A: The answer for the above mentioned question is given in the below steps for your reference.
Q: registers are not included in Bus Interface Unit of 8086 microprocessor. a. BX, SI, D! b. AX, BX, BP…
A: 8086 Microprocessor has two Functional unit Executive Unit (EU) Bus Interface Unit (BIU)
Q: 156. Interrupt addresses are stored in a. array b. stack c. indexes d. queue
A: Given that, Interrupt addresses are stored in a. array b. stack c. indexes d. queue
Q: The Stack segment part of the microcomputer’s memory address space must contain read/write storage…
A: Figure illustrates the segmentation of memory. In this diagram, the 64Kbyte segments are given.…
Q: Draw the isa architecture and describe it register organization?
A: Given: Draw the isa architecture and describe it register organization?
Q: Explain why 8086 Microprocessor have Data line 16 bit and Address line 20 bit.
A: 8086 microprocessor :- 8086 microprocessor is the enhanced and advanced version of 8085…
Q: Identify the instruction format organization used in the following instruction: R1 – R2 O a. Data…
A: The arrangement of the registers in the processor is referred to as register organization. The…
Q: ** Given the following register values of an 8086 microprocessor: DS: BF10H SS:C100H BX :2123H SP:…
A: answer will be: 2128H
Q: 8086 Microprocessor is having 16-bit data bus and 20-bit Address bus Select one: O True O False
A: the above answer is an : true
Q: n ____________, the operand is provided as part of the instruction. a. Register Addressing…
A: It is high-speed circuit in a computing device that hold the addresses of data.Data is in the…
Q: (b) Write down assembly language codes for basic memory locations and addressing operations with…
A: Each family of processors has its own set of instructions for handling various operations such as…
Q: An instruction is stored at location 100 with its address field at location 101.The address field…
A:
Q: 8. Performance of microprocessor is measured in what is called million instructions they can execute…
A: 8.Clock speed 9..Destination index 10.The address part of instructions holds the begining base…
Q: 8086 Microprocessor and Interfacing: reference questions. Q1) Write an ALP to perform multiplication…
A: +4 in hexadecimal = 00000100 = 04H -5 in hexadecimal = (2's complement of 5) = 11111011= FBH
Q: A micro-instruction format has micro-ops field which is divided into three subfields F1, F2, F3 each…
A: The micro-instruction consists of three fields. Fields of microoperation F1,F2,F3 Status bits on a…
Q: Depending on MC68008 microprocessor complete the following table Signal Address bus Input/Output…
A: MC68008: The MC68008 is a member of the M68000 family of advanced microprocessors. Thisdevice allows…
Q: Design microprocessor 8086 memory system consisting of 1M byte , using
A: Here we design a microprocessor 8086 memory system consisting of 1M byte: which consist: 1.128 x 8…
Q: 3. Identify the Offset Register/s needed by the Segment Register to have the Physical Address. a.…
A: The offset Register/s needed by the Segment Register to have the physical address is,
Q: Indirect Addressing Mode Instruction 002A J@ RETADR 3E2003 0030 RETADR RESW 1 1.Instruction Starts…
A:
Q: 1- How to read data from Memory location 0100 by using the figure ? MOV AX,0 0100 0102 0100 Address…
A: It is defined as a control register that holds the location of the next instruction in a pipeline,…
Q: Describe the process of segmentation in 80386 microprocessor
A: GIven Describe the process of segmentation in 80386 microprocessor.
Q: REAL MODE MEMORY ADDRESSING In the real mode, show the starting and ending address of the segment…
A: In real mode, 0H is placed on the rightmost end of the segment value in order to get the starting…
Q: A stack organized computer has a. Three-address Instruction b. Two-address Instruction c.…
A: Computers with Stack-based CPU Organization employ a data structure known as a stack.
Q: MOV AX, BX is an example of
A: MOV AX, BX is an example of
Q: Q1: Explain why 8086 Microprocessor have Data line 16 bit and Address line 20 bit.
A: 8086 Microprocessors have Data line 16 bit and Address line 20 bit because it is designed in such a…
Q: -b. Differentiate between reduced instruction set computer (RISC) and complex instruction set…
A: Reduced Instruction Set Computer: A reduced instruction set computer that is type of microprocessor…
Q: Puestion: Explain. ISA (Instruction Architecture). Types of Architecture) Set ISA( Instruction. set…
A: The instructions set architecture specifies the capability of processor and how it can be…
Q: The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format…
A:
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- Will upvote! Find the memory address of the next instruction executed by the microprocessor, when operated in the real mode, for the following CS:IP and 80286 register combinations: a. DS=2F2E & DX=9D64 b. CS=9F7A & IP=AB27 c. ES=DE21 & DI=D75F d. SS=FF5C & BP=92B8 e. DS=DC67 & CX=2FE8Q1:Suppose the initial physical address of a segment register is given by 0E41:A02EH. Determine the physical address, base and final address of that segment register of 8086 microprocessor16. Compare direct mapping, fully associative mapping and set associative mappingin cache memory.
- 1. Name all of the general purpose registers and some of their special functions. 2. How are the segment registers used to form a 20-bit address? 3. (a) If CS contains 03E0H and IP contains 1F20H, from what address is the next instruction fetched? (b) If SS contains 0400H and SP contains 3FFEH, where is the top of the stack located? (c) If a data segment deigns at address 24000H, what is the address of the last location in the segment? 4. Explain what the instruction array and data caches are used for. 5. What is the EU and BIU, and what purpose in the microcomputer? 6. Two memory locations, beginning at address 3000H, contain the bytes 34H and 12H. What is the word stored at location 3000H? See Figure 2.26 for details. Address 3000 Data 34 3001 12 Figure 2.26 For question 6 7. What is a physical address? What are the differences between the 8086 logical and physical memory maps? 8. May memory segments overlap? If so, what is the minimum number of overlapped bytes…Please solve Q) which is a valid offset pair? A) DS:DI C) ES:SI B) CS:SP D) SS:BP Q) The number of General Purpose Registers present in 8086 microprocessor? 6 10 34 4 Q) With 20-bit address lines memory size of microprocessor would be? Q) Calculate the physical address of the segment offset pair 7213:5686 77686H 0C899H 777B9H 777B6H Q) ALU of 8086 is 20 bit 8 bit 16 bit 32 bit Q) Memory size of 8086 microprocessor is 4KB 256 bytes 128bytes 1MB Q) In 8086 data access by which register uses SS as the default segment register? Both SP and BP SP Dl BP Q) Flag resister is None of the above 20 bit 16 bit 8 bit Q) The starting address of the segment is called None of the above Effective address Base address Offset address Q) Instruction queue size in 8086 is 4 bytes 4 bits 6 bytes 6 bits Q) MOV CX, [481d] ; assuming DS= 2162H, logical address will be: Q) AL= 53 CL=29 ADD AL, CL DAA What is the value of AL after…In an x86-64 system, how many shorts can be stored in a cache block if your cache is 8KB (total addressable locations in cache), is 4-way set-associative, and contains 32 sets? Question 3 options: 8 16 32 64
- cs 218 assembly language Given the code fragment: list1 dd 2, 3, 4, 5, 6, 7 mov rbx, list1 add rbx, 4 mov eax, dword [rbx] mov edx, dword [list1+8] imul dword [list1] What would be in the eax and edx registers after execution (in hex)? eax edx Must answer in hex (must precede number with 0x).Can you describe the challenges involved in developing a cache replacement strategy that is compatible with any and all address sequences?1. Suppose 8 bit registers have following contentsX=00001111Y=10101010Z= 11011011W=00110011What will be the 8 bit values of each register after execution of following sequences ofmicrooperations ?X ← ? + ?Z←Z⋀ ?, ? ← ? + 1X←X-Z
- Please help with the following in regards to Nand2Tetris, and hack code, so hack assembly and hack vm. There can be more that one answer to a question if so please explain why. 1a. The A-instruction in the Hack computer performs a. direct addressing. b. immediate addressing. c. indirect addressing. d. bitwise addressing. 1b. Each memory address in the Hack computer references a. a single byte. b. a single word. c. multiple words. d. the D-register 1c. Given the following assembly code: (FOO) @FOO 0;JMP The purpose of the code is to : a. test of the value is = = 0 NO-OP b. jump to address 0 in RAM c. return a 0 to the calling code d. create an endless loop e. end the assembly language program 1d. Given a function called foo() that calls another external function bar() which in turn calls a second function called additup(). Indicate the VM line of code indicating the location in the program that control should be return to: a.@Foo.$bar. b. @Foo$bar$additup.ret.1 c.…Will upvote! Suppose that ES= 6DF2, DS=83AC, SS=EBD2, AX=B75, DI=DC7, BP=51A, SI=FB3, REN=75D and YEN=A8E. Determine the address accessed by each of the following instructions and state what addressing mode is used: a. MOV REN[DI][AX][9F], BX b. MOV BL, YEN[BP+SI-72A]cs 218 assembly language Given the code fragment: lst dd 2, 3, 5, 7, 9 mov rsi, 4 mov eax, 1 mov rcx, 2 lp: add eax, dword [lst+rsi] add rsi, 4 loop lp mov ebx, dword [lst] What would be in the eax and ebx registers after execution (in hex)? eax ebx Must answer in hex (must precede number with 0x) .