Starting with 0.0116 M Cu2* and 0.230 M NH3 and forming Cu(NH3)42+ ion (Kf = 1.10x1013), determine the equilibrium concentrations of all species. Give your answers in exponential format (e. g. 1.23E-2). Cu2+ = M NH3 = M Cu(NH3)42* M

Starting with 0.0116 M Cu2* and 0.230 M NH3 and forming Cu(NH3)42+ ion (Kf = 1.10x1013), determine the equilibrium concentrations of all species. Give your answers in exponential format (e. g. 1.23E-2). Cu2+ = M NH3 = M Cu(NH3)42* M

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter12: Gaseous Chemical Equilibrium

Section: Chapter Questions

Problem 80QAP: Hydrogen iodide gas decomposes to hydrogen gas and iodine gas: 2HI(g)H2(g)+I2(g)To determine the...

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Question

Starting with 0.0116 M Cu2* and 0.230 M NH3 and forming Cu(NH3)4²+ ion (Kf = 1.10x1013), determine the equilibrium concentrations of all species. Give your
answers in exponential format (e. g. 1.23E-2).
Cu2+ =
M
NH3 =
M
Cu(NH3)42*
M

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