State the value of each variable and whether the variable is basic or non-basic, using the provided final simplex tableau. S1 82 constant 3 1 2 21 -4 -3 -8 1 30 1 1 215 x: y: z: S2: P: n. n. n. n.
Q: Find the solutions that can be read from the simplex tableau given below. X1 X2 X3 S1 S2 S3 13 91 6.…
A: The given simplex table is By using simplex tableau method. ∆2=0, ∆3=0, ∆5=0 Therefore x2, x3 and…
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Q: How do you find the final simplex tableau?
A: (a) Set up the LPP as follows.
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Q: Find the solutions that can be read from the simplex tableau. X1 X2 X3 S1 S2 6. 1 4 77 1 6. 1 -2 1…
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Q: Consider the simplex tableau given below. X1 X2 S1 $2 S3 4 1 1 6 3 3 1 10 2 1 -4 -2 1 4 A) The pivot…
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Q: Use the indicated entry as the pivot and perform the pivoting. X2 X3 S1 S2 S3 Z. 1 11 4 54 1 20 2 -1…
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Q: Consider the simplex tableau given below. X1 X2 X3 S1 S2 S3 1 2 22 1 - 5 27 - 4 2 4 1 19 P.
A: The basic variables gives the identity matrix Therefore the basic variables are as follows
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A: This can be solved as follows:
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Q: Use the indicated entry as the pivot and perform the pivoting. X1 X2 X3 S1 S2 S3 2 1 1 13 1 2 4 1 59…
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A: The given simplex tableau is: x1x2x3s1s2z7-11020275-2012017-8-100-2117
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State the value of each variable and whether the variable is basic or not, using the provide final simplex tableau.
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- Which of the following is the converted constraint of 3x + 2y ≥ 35 under minimization of profit in simplex method? a 3x + 2y - S1 + A1 = 35 b. 3x + 2y + S1 + A1 = 35 c. 3x + 2y + S1 - A1 = 35 d. 3x + 2y - S1 - A1 =-35 e. 3x + 2y - S1 + A1 =-35Find the optimal solution for the following model using simplexState the corresponding corner point for the given simplex tableau. x y s1 s2 s3 P constant 8 0.25 1 0 0 0 72 6 3 0 1 0 0 17 4 0.75 0 0 1 0 67 −2 −3 0 0 0 1 0 The corresponding corner point is (x, y) =
- Determine the solutions of the LP model below using simplex method. Complete Tableaus 1 and 2 below by supplying the values for the items in red. Maximize: P=15x1 + 13x2 Subjec to: x1 ≤ 300 (place in R11) 2x1 + 3x2 ≤ 360 (place in R21) 3x1 + 5x2 ≤ 270 (place in R31) x1 ≥ 0, x2 ≥ 0Question4: The simplex table obtained from an enterprise that produces three products under three constraints: machine hours, raw materials and meeting demand is given.Write down the primary and binary results and how the conclusion was reached.X₁ = ?X₂ = ?X₃ = ?S₁ = ?S₂ = ?S₃ = ?L₁ = ?L₂ = ?2. Use the standard simplex method to solve using your first pivot choice. Provide the sequence of points given in the tableau. Maximize: P=5x+4y Subject to: 2x+y<=80 2x+3y<=120 4x+y<=160 x>=0,y>=0
- Question4: The simplex table obtained from an enterprise that produces three products under three constraints: machine hours, raw materials and meeting demand is given. Write the primal and dual results. X₁ = ? X₂ = ? X₃ = ? S₁ = ? S₂ = ? S₃ = ? L₁ = ? L₂ = ?Use the non-standard simplex method to solve. Show work by setting up the initial simplex tableau (with the columns labeled), circling the first pivot element, and giving the final simplex tableau. If there is no solution, then state which type: Not Feasible or Unbounded. If the solution is unique, then provide the solution with context. If there are infinite solutions, then describe the line segment containing the solutions by providing the two end points. Maximize: P=0.15x+0.17y subject to: 1.10x+1.30y<=5400 x+y>=5000 x>=0, y>=0You are developing a linear program with two decision variables (X1 and X2). Which of thee is Not a correct way to write out the non-negativity constraint? A: All decision variables >=0 B: X1>= 0 an X2>= 0 C- All of these are correct ways to write the non-negativity constraint D: X1, X2>=0 E: X1+X2>=0
- Consider the following simplex tableau. x y z s1 s2 s3 P constant -10 0 0 -1 3 1 0 300 −6 1 0 −5 1 0 0 2,750 −7 0 1 2 8 0 0 14 9 0 0 −4 −1 0 1 540 (a) State the value of each variable. x= y= z= s1= s2= s3= P= State whether the variables are basic or non-basic. x y z s1 s2 s3 P (b) Is the given simplex tableau a final tableau?Solve the following LPP using the simplex / Big M Method Maximize Z= 6X1+8X2 Subject to constraints 2X1+5X2 ≤ 40....................(i) 8X1+4X2 ≤ 80 ...................(ii) where X1 , X2 ≥ 0Consider the following intermediate tableau (not the Initial Simplex tableau): p x1 x2 s1 s2 rhs 0 0 1 1/2 -1/2 3/2 0 1 0 1/2 1/2 5/2 1 0 0 2 -1 7 a) Determine the pivot column and the pivot element, and perform all the row operations for the entire pivot column to obtain the next new tableau. Once you have the new tableau, look at the numbers you have in the objective row and enter each one as requested in each box below. Note: Where applicable, fractions must be entered as 2/5, -1/3, and so on. Under column x1 in the objective row, you have: Under column x2 in the objective row, you have: Under column s1 in the objective row, you have: Under column s2 in the objective row, you have: Under column RHS in the objective row, you have: b) Given the new tableau that you obtained above, three interpretations are possible. In the box below, type or copy and paste whichever answer shown in boldface letters below that you think…
