Use the indicated entry as the pivot and perform the pivoting. X₁ X2 X3 S₁ z $2 1 2 4 1 0 0 66 2 2 1 0 1 0 54 6 -7 -5 0 0 1 0 Complete the following simplex tableau to show the result of the pivoting. x₁ X₂ X3 (Simplify your answers.) min 4 4 =
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- Use the non-standard simplex method to solve. Show work by setting up the initial simplex tableau (with the columns labeled), circling the first pivot element, and giving the final simplex tableau. If there is no solution, then state which type: Not Feasible or Unbounded. If the solution is unique, then provide the solution with context. If there are infinite solutions, then describe the line segment containing the solutions by providing the two end points. Maximize: P=0.15x+0.17y subject to: 1.10x+1.30y<=5400 x+y>=5000 x>=0, y>=0Answer the given question with a proper explanation and step-by-step solution. Please provide the answer using the math tool otherwise I give the downvote. Consider the simplex tableau given below. x1 x2 1 4 0 -2 0 -5 0 1 0 (A) Which variables are basic variables? O x₁,S₁, and S₂ X₁,S₁, and P X2,S2, and P X2,S₁,and S2 X2 and s₂ S2 and P $₂ 3 4 -3 Which variables are nonbasic variables? X₂ and s₁ S₁, and $2 P 0 0 1 19 25 10 (B) Find the corresponding values from the tableau above. ×₁=?Apply elimination (circle the pivots) and back substitution to solve2x - 3y = 34x - 5y + z = 72x - y - 3z = 5.55List the three row operations: Subtract -? times row -? from row -?.
- Determine the solutions of the LP model below using simplex method. Complete Tableaus 1 and 2 below by supplying the values for the items in red. Maximize: P=15x1 + 13x2 Subjec to: x1 ≤ 300 (place in R11) 2x1 + 3x2 ≤ 360 (place in R21) 3x1 + 5x2 ≤ 270 (place in R31) x1 ≥ 0, x2 ≥ 0 Consider the simplex tableau given below. (A) Where is the pivot element is located? (B) What is the entering variable (C) What is the exiting variable (D) Show the values after one pivot operation in the tableauQ3 Solve the following linear programing problem by using the Simplex method:Maximize Subject toAnd? = 4x + 3y x+ y ≤ 53x + 2y ≤ 12 x, y ≥ 0
- Use the simplex method to solve the problem: Maximize: P = 3x1 + 2x2 subject to: 5x1 + 2x2 ≤ 20 3x1 + 2x2 ≤ 16 x1 ≥ 0, x2 ≥ 0Use method of Lagrange multipliers to find the optimal solution. y= 20A-101.5V phi= A(230-47.7/V) - 5556 =0hat is the average of the two solutions of the abitrary quadratice equation ax2 + bx +c = 0
- max z = 2x1 + 3x2 s.t. 2x1 + 4x2 ≤ 8 2x1 + 3x2 ≤ 9 x1, x2 ≥ 0 For the starting basic feasible solution x1 = 0, x2 = 0, s1 = 8, and s2 = 9, the corresponding Simplex tableau is:Q3- Find the optimum values of X1, X2 and X3 that maximize the values of Z using simplex method? Maximize Z= 3X1+ 4X2+X3 Subject to 3X1 +10X2 +5X3 <120 5X1 +2X2 +8X3<6 4X1 +10X2 +3X3 < 105 X1,X2,X3 >02. Use the standard simplex method to solve using your first pivot choice. Provide the sequence of points given in the tableau. Maximize: P=5x+4y Subject to: 2x+y<=80 2x+3y<=120 4x+y<=160 x>=0,y>=0