Step 2So, the volume of the solid of revolution isVolume = V = Tt(25 – x2)2 dx.To find the volume, integrate from x = 0to x = 5.V = TtJo- 50x2+ 625) dx50x+ 625= IT50 · 5+ (625 · 5– 0)-03125+ 31253.15

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Step 2 So, the volume of the solid of revolution is Volume = V = Tt (25 – x)2 dx. To find the volume, integrate from x =0 to x = 5. V = T (x4 - 50x2 + 625) dx 50x + 625 3 50 - (625 - 5 – 0) 3125 +3125 15

Step 2 So, the volume of the solid of revolution is Volume = V = Tt (25 – x)2 dx. To find the volume, integrate from x =0 to x = 5. V = T (x4 - 50x2 + 625) dx 50x + 625 3 50 - (625 - 5 – 0) 3125 +3125 15

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...

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Question

100%

Step 2
So, the volume of the solid of revolution is
Volume = V = Tt
(25 – x2)2 dx.
To find the volume, integrate from x = 0
to x = 5.
V = Tt
Jo
- 50x2
+ 625) dx
50x
+ 625
= IT
50 · 5
+ (625 · 5– 0)
-0
3125
+ 3125
3.
15

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