Step 3 of 5 In order to maximize V(x), we need to find the critical points of V(x). Find the derivative of V(x) = x(30 - 2x)(36 - 2x) = 4(x³ – 33x2 + x). %3D V'(x) = 12( Submit Skip_(you cannot come back)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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Find the intersection of these two solutions.
15
Thus the domain of V(x) in interval notation is (0, 15)
(0,15) inches.
Step 3 of 5
In order to maximize V(x), we need to find the critical points
of V(x).
Find the derivative of V(x) = x(30 – 2x)(36 – 2x) = 4(x² – 33x +
x).
V'(x) = 12
Submit Skip (you cannot come back)
P Type here to search
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Transcribed Image Text:M CPCC Email MyCollege Blackboard Brightspace CPCC CPCC Bookstore Find the intersection of these two solutions. 15 Thus the domain of V(x) in interval notation is (0, 15) (0,15) inches. Step 3 of 5 In order to maximize V(x), we need to find the critical points of V(x). Find the derivative of V(x) = x(30 – 2x)(36 – 2x) = 4(x² – 33x + x). V'(x) = 12 Submit Skip (you cannot come back) P Type here to search hp
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