Step 3 The integral 27 12xe dx can be done with the substitution u = 2 and du %3D -2x dx. -2.r Step 4 With the substitution, we have 2n | 12xe-x dx = - 127 eu du 127 12ne + C. 12me" Step 5 Going back to x, the volume of our solid is = 144

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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Solve step 5 only

Step 3
The integral 2n
12xex
dy can be done with the substitution u =-x
and du
|-2x
dx.
-2.r
Step 4
| 12xex dx = - 127
With the substitution, we have 2n
eu du
127
|12ле
+ C.
12ze"
Step 5
Going back to x, the volume of our solid is
144
Transcribed Image Text:Step 3 The integral 2n 12xex dy can be done with the substitution u =-x and du |-2x dx. -2.r Step 4 | 12xex dx = - 127 With the substitution, we have 2n eu du 127 |12ле + C. 12ze" Step 5 Going back to x, the volume of our solid is 144
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