V-9+16"| dx 1. 16* 2. arctan(Vx – 2)dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi! I'm having a hard time with trig substitution & integration by parts so I hope these 2 will be answered. Thanks

Apply INTEGRATION BY PARTS only (Sudv= uv- Svdu.) use trigonometric integrals and
Integration by Trigonometric Substitution.
-9+ 16*
-dx
1.
16*
2.
arctan(væ – 2)dx
For reference:
trig integrals:
sin" xdx, where mENand m is odd
• split off a factor of sinx
• express the rest of the factors in terms of cos.x using sin² x = 1 – cos? x
• use the substitution u= cos x, du= - sin.xdx
sin" xdx or
cos" xdx, where mɛNand mis even
• express sin"x= (sin² x)"™/2 or cos"x= (cos²x)m/2
• use the half-angle identity
cos²x= -(1+ cos 2x) or sin?x=÷(1- cos2x)
cases for trig substitution:
Case 1. Va – u² =let u= asin0, so vď – u² = acos0
Case 2. Vu – a² =let u= asec0, so vư – á² = atan0
Case 3. Va? + ư =
let u = atan0, so va² + u² = asec0
Transcribed Image Text:Apply INTEGRATION BY PARTS only (Sudv= uv- Svdu.) use trigonometric integrals and Integration by Trigonometric Substitution. -9+ 16* -dx 1. 16* 2. arctan(væ – 2)dx For reference: trig integrals: sin" xdx, where mENand m is odd • split off a factor of sinx • express the rest of the factors in terms of cos.x using sin² x = 1 – cos? x • use the substitution u= cos x, du= - sin.xdx sin" xdx or cos" xdx, where mɛNand mis even • express sin"x= (sin² x)"™/2 or cos"x= (cos²x)m/2 • use the half-angle identity cos²x= -(1+ cos 2x) or sin?x=÷(1- cos2x) cases for trig substitution: Case 1. Va – u² =let u= asin0, so vď – u² = acos0 Case 2. Vu – a² =let u= asec0, so vư – á² = atan0 Case 3. Va? + ư = let u = atan0, so va² + u² = asec0
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