Step 3 The integral 27 12xe-x? dx can be done with the substitution u = 2 X- and du = -2x dx. -2.x Step 4 With the substitution, we have 27 12xe-x2 dx eu du + С. %3D Submit Skip (you cannot come back)

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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Step 3
The integral 27
12xe-x?
dx can be done with the substitution u =
2
X-
and du =
-2x
dx.
-2.x
Step 4
With the substitution, we have 27
12xe-x2
dx
eu du
+ С.
%3D
Submit
Skip (you cannot come back)
Transcribed Image Text:Step 3 The integral 27 12xe-x? dx can be done with the substitution u = 2 X- and du = -2x dx. -2.x Step 4 With the substitution, we have 27 12xe-x2 dx eu du + С. %3D Submit Skip (you cannot come back)
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