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Step 4 To minimize the product f(x) = x² + 170x, we must solve 0 = f '(x) = 2x + 170, which means X = |-85 -85 Step 5 Since f "(x) there must be an absolute minimum at x = -85. Thus, the two numbers are as follows. (smaller number) (larger number)

Step 4 To minimize the product f(x) = x² + 170x, we must solve 0 = f '(x) = 2x + 170, which means X = |-85 -85 Step 5 Since f "(x) there must be an absolute minimum at x = -85. Thus, the two numbers are as follows. (smaller number) (larger number)

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CR: Review Problem Set
Problem 37CR
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I need step 5 please

If two numbers have a difference of 170, and one of them is x + 170, then the other is -85, 85 Step 2 The product of two numbers x and x + 170 can be simplified to be x + 170 170 x. Step 3 If f(x) = x2 + 170x, then f '(x) = 2x + 170 2л + 170 Step 4 To minimize the product f(x) = x2 + 170x, we must solve 0 = f '(x) = 2x + 170, which means X = -85 -85 Step 5 Since f "(x) there must be an absolute minimum at x = -85. Thus, the two numbers are as follows. (smaller number) (larger number)
Transcribed Image Text:If two numbers have a difference of 170, and one of them is x + 170, then the other is -85, 85 Step 2 The product of two numbers x and x + 170 can be simplified to be x + 170 170 x. Step 3 If f(x) = x2 + 170x, then f '(x) = 2x + 170 2л + 170 Step 4 To minimize the product f(x) = x2 + 170x, we must solve 0 = f '(x) = 2x + 170, which means X = -85 -85 Step 5 Since f "(x) there must be an absolute minimum at x = -85. Thus, the two numbers are as follows. (smaller number) (larger number)
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