Student's attempt Let X = the number of accidenty X ~ Po(0.8) The possible values of X are 1, 2, 3,s P(X > 2) = 1 - [P(X=1) +P(X =2)] e*0.8' $0.82 - 1 - (0.35946 + 0.14379) = 1 - 0.49675 %3D 1! 2!
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A Statistics student was asked to solve the problem below. See the student’s attempt at the question and list all of the errors. Correct the errors to solve the question.
Question: An average of 0.8 accidents occur every day on the roads of Trinidad and Tobago. Find the probability that at least 2 accidents will occur in Trinidad and Tobago on a given day.
![Student's attempt
Let X = the number of accidenty
X ~ Po(0.8)
The possible values of X are 1, 2, 3,s
P(X > 2) = 1 - [P(X=1) +P(X =2)]
e*0.8'
$0.82
- 1 - (0.35946 + 0.14379) = 1 - 0.49675
%3D
1!
2!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7c7d68f-541e-4183-87b8-b84bb390b82a%2F8fd71220-c81e-4d87-a028-8446fc55ef7b%2F33j18n.png&w=3840&q=75)
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