Step 3Substituting the simplified numerator back into the derivative formula and simplifying, we have56х — 56аf'(a) = lim(х + 8)(а + 8)XaX — а56limх — а%Da(x + 8)(a + 8)(x – a)56lim56Xa(х + 8)(а + 8)Step 4Evaluating this limit, and replacing a with t and f with G, we conclude that the derivative is as follows.56G'(t)(1+b)?SubmitSkip (you cannot come back)

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Substituting the simplified numerator back into the derivative formula and simplifying, we have 56х — 56а f'(a) lim (x + 8)(a + 8) х — а 56 lim х — а r - a Xa (x + 8)(a + 8)(x – a) 56 = lim 56 Xa (x + 8)(a + 8) Ftep 4 Evaluating this limit, and replacing a with t and f with G, we conclude that the derivative is as follows. 56 G'(t) = (1+b)²

Substituting the simplified numerator back into the derivative formula and simplifying, we have 56х — 56а f'(a) lim (x + 8)(a + 8) х — а 56 lim х — а r - a Xa (x + 8)(a + 8)(x – a) 56 = lim 56 Xa (x + 8)(a + 8) Ftep 4 Evaluating this limit, and replacing a with t and f with G, we conclude that the derivative is as follows. 56 G'(t) = (1+b)²

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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