Fill in the blank where the pink is. Sulfur-38Original amount: 5.0 gAmount left: rTotal time: 8.61 hHalf-life: 2.87 hNumber of half-lives:

Answered: Image /qna-images/answer/1f98c309-61c1-4fd6-bc00-2665a2081c6a.jpg

Answered: Sulfur-38 Original amount: 5.0 g Amount…

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter20: Nuclear Chemistry

Section: Chapter Questions

Problem 17E

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Similar questions

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The streptomycin in 500 g of a broth was determined by addition of 1.25 mg of the pure antibiotic containing 14C. The specific activity of this preparation was found to be 240 cpm/mg for a 30-min count. From the mixture, 0.112 mg of purified streptomycin was isolated which produced 675 counts in 60.0 min. Calculate the concentration in parts per million streptomycin in the sample.
The isotope S3890r one of the extremely hazardous species in the residues from nuclear power generation. The strontium in a 0.500-g sample diminishes to 0.393 g in 10.0 y. Calculate the half-life.
The activity after irradiation is 10 Ci (Hf-175, T1/2 = 70 d).I. What amount must be sent (in ml) (delivery time 5 days) so that the customer receives1 Ci (20GBq / ml), alsoII. calculate the amount of 0.04M HCl that must be added to the initial activity.
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-24 (24Na) is a radioisotope used to study circulatory dysfunction. A measurement found 5 micrograms of 24Na in a blood sample. A second measurement taken 6 hrs later showed 3.80 micrograms of 24Na in a blood sample. Find the half-life in hrs of 24Na. Round to the nearest tenth.
1 The half-life of protactinium-217 is 4.9 x 10-3s. How much of a 3.50 mg sample of 21791 Pa will remain after 1.00 second? Can you please show work using ln(Nt/No)=-kt equation? thank you so much!
The half-life of 27Mg is 9.50 min. (a) Initially there were 3.60 ×1012 27Mg nuclei present. How many 27Mg nuclei are left 24.5 min later? Please give your answer to 2 significant figures.Enter your answer in scientific notation. (b) Calculate the 27Mg activities (in Ci) at t = 0 and t = 24.5 min.

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Sulfur-38 Original amount: 5.0 g Amount left: c Total time: 8.61 h Half-life: 2.87 h Number of half-lives: