Sulphur presents two lines: Ka₁= 5.37216 Å and Ka₂= 5.37496 Å 1. What is the energy difference expressed in eV, between Ka₁ and Kα₂ 2. If it is known that the width at the mid-height of these lines is 5 eV, what conclusion can be drawn 3. If the position of the Ka₂ line increases by 0.002 Å when passing from S6+ to Sº, show that this has no impact upon the location of this photoelectron in energy terms

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter5: Electron Configurations And The Periodic Table
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Sulphur presents two lines: Ka₁= 5.37216 Å and Ka₂= 5.37496 Å
1. What is the energy difference expressed in eV, between Ka₁ and Kα₂
2. If it is known that the width at the mid-height of these lines is 5 eV, what conclusion can be
drawn
3. If the position of the Ka₂ line increases by 0.002 Å when passing from S6+ to Sº, show that
this has no impact upon the location of this photoelectron in energy terms
Transcribed Image Text:Sulphur presents two lines: Ka₁= 5.37216 Å and Ka₂= 5.37496 Å 1. What is the energy difference expressed in eV, between Ka₁ and Kα₂ 2. If it is known that the width at the mid-height of these lines is 5 eV, what conclusion can be drawn 3. If the position of the Ka₂ line increases by 0.002 Å when passing from S6+ to Sº, show that this has no impact upon the location of this photoelectron in energy terms
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