In masm x86 assembly languageSCREEN. SHOT. THE. RESULT.implement code below sum = 0i=0j = 12var1 = 3var2 = 3var3 = 0while(i var3){var1 =var1 - i;}else {var3 = var3+ i;}sum var1 + var2+ var3;j=j-1i=i+1}- if you code it correctly, at the end sum contains 15 (decimal).- assume that variables are 32-bit signed integers variables- you are not allowed to make any logical reduction to the code. You need to implement it the way it isprovided.

Assembly language: Assembly language is a low level programming language. It is used to directly…

Answered: sum = 0 i=0 j = 12 var1 = 3 var2 = 3…

sum = 0 i=0 j = 12 var1 = 3 var2 = 3 var3 = 0 while(i var3){ var1 =var1 - i; } else { var3 = var3+ i; } sum var1 + var2+ var3; j=j-1 i=i+1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

In masm x86 assembly language

SCREEN. SHOT. THE. RESULT.

implement code below

sum = 0
i=0
j = 12
var1 = 3
var2 = 3
var3 = 0
while(i<j){
if (var1 > var3){
var1 =var1 - i;
}
else {
var3 = var3+ i;
}
sum var1 + var2+ var3;
j=j-1
i=i+1
}
- if you code it correctly, at the end sum contains 15 (decimal).
- assume that variables are 32-bit signed integers variables
- you are not allowed to make any logical reduction to the code. You need to implement it the way it is
provided.

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