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SUPPLEMENT: The human body is 0.4% potassium by weight. 0.0117% of all potassium is 4°K. Calculate the rate of decay (dpm) experienced by the average person due to 4°K within their own body. Assume an average weight of 155 lb (70.5 kg). person's weight in grams grams K g grams 40K g moles 4°K moles atoms 4°K atoms 40K beta decay rate constant min- k = ( In 2 ) / ( t,2) decay rate of 40K in body dpm dpm = (k )( atoms 4°K ) This is a much higher decay rate that was produced by the sample of compound in the experiment. But if the probe were held next to your body, practically none would be detected. Explain why.

SUPPLEMENT: The human body is 0.4% potassium by weight. 0.0117% of all potassium is 4°K. Calculate the rate of decay (dpm) experienced by the average person due to 4°K within their own body. Assume an average weight of 155 lb (70.5 kg). person's weight in grams grams K g grams 40K g moles 4°K moles atoms 4°K atoms 40K beta decay rate constant min- k = ( In 2 ) / ( t,2) decay rate of 40K in body dpm dpm = (k )( atoms 4°K ) This is a much higher decay rate that was produced by the sample of compound in the experiment. But if the probe were held next to your body, practically none would be detected. Explain why.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter18: Nuclear Chemistry
Section: Chapter Questions
Problem 18.ACP
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SUPPLEMENT: The human body is 0.4% potassium by weight. 0.0117% of all potassium is 4°K. Calculate the rate of decay (dpm) experienced by the average person due to 40K within their own body. Assume an average weight of 155 lb (70.5 kg). person's weight in grams g grams K grams 40K g moles 4°K moles atoms 40K atoms 40K beta decay rate constant min-1 k = ( In 2 ) / ( t,2 ) decay rate of 40K in body dpm dpm = (k )( atoms 40K ) %3D This is a much higher decay rate that was produced by the sample of compound in the experiment. But if the probe were held next to your body, practically none would be detected. Explain why.
Transcribed Image Text:SUPPLEMENT: The human body is 0.4% potassium by weight. 0.0117% of all potassium is 4°K. Calculate the rate of decay (dpm) experienced by the average person due to 40K within their own body. Assume an average weight of 155 lb (70.5 kg). person's weight in grams g grams K grams 40K g moles 4°K moles atoms 40K atoms 40K beta decay rate constant min-1 k = ( In 2 ) / ( t,2 ) decay rate of 40K in body dpm dpm = (k )( atoms 40K ) %3D This is a much higher decay rate that was produced by the sample of compound in the experiment. But if the probe were held next to your body, practically none would be detected. Explain why.
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