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Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is:

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is:

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Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.

The current in the light bulb is:

Content Take Test: Q4 Culminating PeTa - x O Claned i ust.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_338107_1&course_id=_134073_1&content_id=_4931742_18&step=null * Question Completion Status: È = - 7d ar Evaluating the differential, we, get the following 1 È = *(q/ 4πεο QUESTION 3 25 points Save Answer Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: | = milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 x 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons QUESTION 4 25 points Save Answer Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Window Save and Submit (a ENG 10:01 am
Transcribed Image Text:Content Take Test: Q4 Culminating PeTa - x O Claned i ust.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_338107_1&course_id=_134073_1&content_id=_4931742_18&step=null * Question Completion Status: È = - 7d ar Evaluating the differential, we, get the following 1 È = *(q/ 4πεο QUESTION 3 25 points Save Answer Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: | = milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 x 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons QUESTION 4 25 points Save Answer Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Window Save and Submit (a ENG 10:01 am
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