Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is:milliamperesThe total amount of charge passing through the filament in t= 5.00 s is:Q =coulombsSince a single electron has a charge of -1.60 x 10-19 C, the number of electrons passing through the filament int=5.00 s is:N =x 1019 electrons

Given The charge flow through the filament in 2 sec is Q=1.67 C. The time up to which Q charge is…

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter17: Current And Resistance

Section: Chapter Questions

Problem 18P: The current supplied by a battery in a portable device is typically 0.15 A. Find the number of...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.

The current in the light bulb is:
milliamperes
The total amount of charge passing through the filament in t= 5.00 s is:
Q =
coulombs
Since a single electron has a charge of -1.60 x 10-19 C, the number of electrons passing through the filament in
t=5.00 s is:
N =
x 1019 electrons

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