Suppose (-2,1) is a critical point of f(x, y) and that the Second Derivative Test applies to f(x, y). What can you say about the values of fz (-2,1) and fy (-2,1)? They are [ Select] Suppose further that frz (-2,1) = 5, fru (–2,1) = 3, and fzy (–2, 1) = –3. What conclusion can you draw based on The Second Derivative Test about the graph of f(x, y) at this critical point? [ Select] [ Select ] There is a saddle point. There is a local maximum. There is a local minimum.

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
ChapterP: Prerequisites
SectionP.6: Analyzing Graphs Of Functions
Problem 6ECP: Find the average rates of change of f(x)=x2+2x (a) from x1=3 to x2=2 and (b) from x1=2 to x2=0.
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Suppose (-2,1) is a critical point of f(x, y) and that the Second Derivative Test applies to f(x, y).
What can you say about the values of fr (-2,1) and fy (-2, 1)?
They are [Select]
Suppose further that frz (-2,1) = 5, fry (-2,1) = 3, and fry (-2,1) = -3. What conclusion can you draw based on The Second Derivative Test about the
graph of f(x, y) at this critical point? [ Select]
[ Select ]
There is a saddle point.
There is a local maximum.
There is a local minimum.
Transcribed Image Text:Suppose (-2,1) is a critical point of f(x, y) and that the Second Derivative Test applies to f(x, y). What can you say about the values of fr (-2,1) and fy (-2, 1)? They are [Select] Suppose further that frz (-2,1) = 5, fry (-2,1) = 3, and fry (-2,1) = -3. What conclusion can you draw based on The Second Derivative Test about the graph of f(x, y) at this critical point? [ Select] [ Select ] There is a saddle point. There is a local maximum. There is a local minimum.
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