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- Suppose that we have the following 128-bit AES key, given in hexadecimalrepresentation:54 77 6F 20 4F 6E 65 20 4E 69 6E 65 20 54 77 6F Construct the round key for the first round.Its a python programming Based on the following Sorted List, show the steps of a Binary Search if the search key was -3: [ -34, -23, -11, -5, 1, 3, 7, 11, 14, 19, 20, 25, 33, 42 ]Show that the following is true: A search miss in a TST built from N random string keys often requires ln N character comparisons. For every search hit or insertion into a TST, a character comparison is performed on each character in the search key.
- 33. How many distinct stages are there in DES algorithm, which is parameterized by a 56-bit key? a. 16 b. 17 c. 18 d. 19Observe the following graph. Identify the nodes and their weights. Encrypt all the weights sothat minimum number of bits are utilized.The ROT-13 algorithm encrypts a string one character at a time by adding 13 to the value of the internal representation of the character. We want our encryption scheme to cover the entire printable ASCII range. After examining the ASCII character set and their internal representations, we see that characters 0 through 32 and character 127 are control characters. Technically, characters 32 (space) and 127 (DEL) are printable, but we don’t want to include them in our encryption routine. Therefore, we want our encrypted string to only contain characters in the range of 33 through 126. As an example: Plaintext: Norwich Ciphertext: [|!&vpu The internal representation of ‘N’ is 78. 78 plus 13 is 91, which is the character ‘[‘. The internal representation of ‘o’ is 111. 111 plus 13 is 124, which is the character ‘|’. The internal representation of ‘r’ is 114. 114 plus 13 is 127. Since 126 is our maximum value for our desired printable range, we…
- A binary code is a string of 0's and 1's. In particular, an n-bit binary code is a string of "n" 0's and 1's. For example, the code "01001" is a 5-bit binary code. How many 5-bit binary codes can be formed?An insertion in an AVL with n nodes requires O(n) rotations. a.)TRUE b.)FALSEProve the following statement: On average, a search miss in a TST constructed from N random string keys needs ln N character comparisons. Each character in the search key is compared in a character comparison for every search hit or insertion into a TST.
- /* * copyLSB - set all bits of result to least significant bit of x * Example: copyLSB(5) = 0xFFFFFFFF, copyLSB(6) = 0x00000000 * Legal ops: ! ~ & ^ | + << >> * Max ops: 5 * Rating: 2 */int copyLSB(int x) { return 2;}implement c# program creates a BitArray of five Byte values (1,2,3,4,5) anddisplays each byte in its proper binary form:for a given data set size of 500, the execution time is .005 micro secondes, if the size of the data grew to 10, 000 what is the execution time for the new data size if the underlying algorithm is: a) O(n) b) log2(n)