Suppose a chemist discovers a new metallic element and names it "Xhaustium" (Xh). Xh exhibits chemical behaviour similar to an alkaline earth. Xh(s) + F2(g) → XhF2(s) Lattice energy for XhF2 -2140. kJ/mol First Ionization energy of Xh 310. kJ/mol Second Ionization energy of Xh 589 kJ/mol Electron affinity of F -327.8 kJ/mol Bond energy of F2 154 kJ/mol Enthalpy of sublimation (atomization) of Xh 150. kJ/mol Use the above data to calculate ΔH°f for Xhaustium fluoride. Your answer must be accurate and precise to the nearest 1 kJ/mol, as are the given parameters.
Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
Suppose a chemist discovers a new metallic element and names it "Xhaustium" (Xh).
Xh exhibits chemical behaviour similar to an alkaline earth.
Xh(s) + F2(g) → XhF2(s)
| Lattice energy for XhF2 | -2140. kJ/mol |
| First Ionization energy of Xh | 310. kJ/mol |
| Second Ionization energy of Xh | 589 kJ/mol |
| -327.8 kJ/mol | |
| Bond energy of F2 | 154 kJ/mol |
| Enthalpy of sublimation (atomization) of Xh | 150. kJ/mol |
Use the above data to calculate ΔH°f for Xhaustium fluoride.
| Your answer must be accurate and precise to the nearest 1 kJ/mol, as are the given parameters. |
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